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erma4kov [3.2K]
2 years ago
14

An operating system that allows a single user to work on two or more programs at the same time is what type of OS?

Computers and Technology
1 answer:
Lisa [10]2 years ago
5 0

Answer:

Explanation:

The correct answer is none of these

An operating system that allows a single user to perform only one task at a time is called a Single-User Single-Tasking Operating System. Functions like printing a document, downloading images, etc., can be performed only one at a time. Examples include MS-DOS, Palm OS, etc.

Advantage: This operating system occupies less space in memory.

Disadvantage: It can perform only a single task at a time.

There are four types of operating systems −

Real-time operating system

Single-User/Single-Tasking operating system

Single-User/Multitasking operating system

Multi-User/Multitasking operating system

Real-time operating system is designed to run real-time applications. It can be both single- and multi-tasking. Examples include Abbasi, AMX RTOS, etc.

An operating system that allows a single user to perform more than one task at a time is called Single-User Multitasking Operating System. Examples include Microsoft Windows and Macintosh OS.

It is an operating system that permits several users to utilize the programs that are concurrently running on a single network server. The single network server is termed as "Terminal server". "Terminal client" is a software that supports user sessions. Examples include UNIX, MVS, etc.

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TRUE/FALSE: In order to use an object in a program, its class must be defined.
FinnZ [79.3K]
Yes that is correct. True
3 0
3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
A thin film transistor (TFT) is a/an______________.
Leviafan [203]

Answer:

Option a electronic switch used on FPDs

Explanation:

A thin film transistor (TFT) is an electronic switch which is commonly used in a liquid crystal display (LCD). TFT derives its name by the way how it is produced. It is produced by layering thin films of semiconductor.  TFT is a type of transistor which is used to control state every  individual pixel in a LCD. TCT can change the states of pixels (on and off) very quickly.

6 0
3 years ago
if a person walks 10 metres due to south in 10 seconds 10 due east in the next 10 seconds and transmitted you're not in the next
Scorpion4ik [409]

Answer:

\frac{1}{3}\ m/s

Explanation:

The computation of the velocity by using the following formula is

As we know that

Velocity = \frac{Displacement}{Total\ time\ taken}

where,

Displacement is 10 meters

Total time taken is 30 seconds

Now placing these values to the above formula

So, the velocity of Dash is

= \frac{10\ meters}{30\ seconds}

= \frac{1}{3}\ m/s

We simply applied the above formula so that we can get the velocity and the same is to be considered

5 0
3 years ago
In your own words! Give me an example of Digital Literacy? (50 words
iVinArrow [24]

Answer: See explanation

Explanation:

Digital literacy is when an individual can compose, find, and evaluate, a clear and composed information on digital platforms.

It involves possessing the skills that one need to live, and learn, through the use of digital platforms such as social media, mobile

Example of digits literacy is the use of search engines, understanding how web browser can be used or sending of emails. etc

3 0
3 years ago
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