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kherson [118]
3 years ago
6

What can be determined from this selection? Check all that apply. The Tax Info worksheet is currently being viewed. There are th

ree worksheets. "Tax Info" will be printed. A chart was made in worksheet 2. Another worksheet can be created.
Computers and Technology
2 answers:
k0ka [10]3 years ago
8 0
Hello!

I believe your answers are . . .  . . . . .  . .

=
<span> There are three worksheets.
= </span>
<span>The Tax Info worksheet is currently being viewed.

Hope this helps!
~Have an awesome day~
</span>
oksano4ka [1.4K]3 years ago
3 0

Answer:

probably as there are 2 spreadsheets could be made to 3 with tax information

Explanation:

Hope this helps :) -Mark Brainiest Please :)

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I don't think so because the old computers may have not been to date as what we have now but check it out and see.
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How do you enlarge your screen if there is no control panel? Need desperate help!
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You hit ctrl than the plus/equal sign Hope that helped! 
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3 years ago
Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo
kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int n,no_open=0;

   cout<<"enter the number of lockers:";

   // read the number of lockers

   cin>>n;

   // initialize all lockers with 0, 0 for locked and 1 for open

   int lock[n]={};

   // toggle the locks

   // in each pass toggle every ith lock

   // if open close it and vice versa

   for(int i=1;i<=n;i++)

   {

       for(int a=0;a<n;a++)

       {

           if((a+1)%i==0)

           {

               if(lock[a]==0)

               lock[a]=1;

               else if(lock[a]==1)

               lock[a]=0;

           }

       }

   }

   cout<<"After last pass status of all locks:"<<endl;

   // print the status of all locks

   for(int x=0;x<n;x++)

   {

       if(lock[x]==0)

       {

           cout<<"lock "<<x+1<<" is close."<<endl;

       }

       else if(lock[x]==1)

       {

           cout<<"lock "<<x+1<<" is open."<<endl;

           // count the open locks

           no_open++;

       }

   }

   // print the open locks

   cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0
3 years ago
PLEASE HELP QUICKLY, I WILL GIVE BRAINLIEST TO THE BEST ANSWER!
dmitriy555 [2]

Answer:

If there are multiple schools in the teams table with the same name, each one of those rows will get joined to matching rows in the players table.

Explanation:

the answer must be match join?

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How can you know if the information is based on scientifically collected data and if it's corroborated by other sources? Follow
Radda [10]

The links redirect the reader to other PETA articles.

Answer: Option A.

<u>Explanation:</u>

A link (short for hyperlink) is a HTML object that permits you to bounce to another area when you snap or tap it. Connections are found on pretty much every site page and give a basic methods for exploring between pages on the web. Connections can be joined to content, pictures, or other HTML components.

A link is a reference to information that the peruser can follow by clicking or tapping. A hyperlink focuses to an entire archive or to a particular component inside a record. Hypertext is content with hyperlinks. The content that is connected from is called stay content.

5 0
3 years ago
Read 2 more answers
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