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Tju [1.3M]
3 years ago
7

ATTENTION I need this ASAP so if you could, please look at the photo. Also this is for 50 points.

Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0
It’s actually 25 not 50 so don’t scam bye
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Exercise 21
Lina20 [59]

Answer:

see explanation

Step-by-step explanation:

area of Δ ABC is calculated as

A = \frac{1}{2} bh ( b is the base and h the height )

Here b = 4x - 6 and h = 2x - 3 , then

A = \frac{1}{2} (4x - 6)(2x - 3) ← expand using FOIL

   = \frac{1}{2}(8x² - 24x + 18) ← distribute

    = 4x² - 12x + 9

----------------------------------------------------------

Area of rectangle CBFG is calculated as

A = lb ( l is length, b is breadth )

Here l = 4x - 6 and b = 3x - 2, then

A = (4x - 6)(3x - 2) ← expand using FOIL

   = 12x² - 26x + 12

----------------------------------------------------------

Area of trapezoid is calculated as

A = \frac{1}{2} h (b₁ + b₂)

where h is the height and b₁, b₂ the parallel bases

Here h = 2x - 3, b₁ = 4x + 1, b₂ = 2x + 3 , then

A = \frac{1}{2} (2x - 3)(4x + 1 + 2x + 3)

   = \frac{1}{2} (2x - 3)(6x + 4) ← expand using FOIL

   = \frac{1}{2} (12x² - 10x - 12) ← distribute

   = 6x² - 5x - 6

5 0
3 years ago
Can y’all help me? i’ll literally fail if i don’t get these right lol
ioda

Answer:

63 degrees.

Step-by-step explanation:

TRaingle ABC is isosceles so the base angles are equal That is < BAC = < BCA.

<BAC = 180 - 117 = 63 degrees ( because it  is adjacent to <x which is 63 degrees).

So < BCA = <BAC = 63 degrees.

Finally y = 63 degrees ( vertical angles are equal).

5 0
3 years ago
In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11
Nataliya [291]
<span>In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11 feet long? The answer is 6.1</span>
4 0
3 years ago
Help me on both parts of b
Ahat [919]

Answer:

Step-by-step explanation:

7 0
3 years ago
A rope 33cm long has a mass of 561g. What is the mass of 13cm of this rope?
Digiron [165]

Answer:

221g

Step-by-step explanation:

561g divided by 33cm is how much 1 cm of rope would be so then you multiply that amount by 13

8 0
4 years ago
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