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3 years ago

Kareem made 195$ for 13 hours of work. At the same rate, how much he make for 11 hours of work?

1 answer:

7 0

He makes 165$ for 11 hours because he makes 195$ in 13 hours so you divide 195 by 13 to get 15$ the amount he earns per hour. After that you just multiply 15 by 11 to get 165$. Hope this helps:)>

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Find the area of the figure Please help :)

ASHA 777 [7]

9514 1404 393

Answer:

372 m²

Step-by-step explanation:

A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.

The area of one of them is ...

A = 1/2(b1 +b2)h

So, the area of the two of them together is ...

A = (2)(1/2)(b1 +b2)h = (b1 +b2)h

A = (13 m + 18 m)(12 m) = 372 m²

6 0

3 years ago

Helppppp!!! What is the area of the trapezoid shown below?

Trava [24]

Answer:

The area of T is equal to sum of area of R and Triangle

Step-by-step explanation:

$area = 12 \times 2$

Area)= 24

$area = \frac{1}{2} \times 12 \times 15$

Area= 90

Area of T = 90 PLUS 24

AREA == 114

<h2>PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE </h2>

4 0

2 years ago

Read 2 more answers

I’m confused on the split circle part; do i count it as a full circle?

OleMash [197]

Answer:

Below.

Step-by-step explanation:

Yes - those are 2 semicircles so their combined area = πr^2

= 3^2π

= 9π.

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Degger [83]

Answer: b) 15.7

Step-by-step explanation:

Look at the z-table (below) to find 0.2500

Notice that the value is not on the table but is between 0.2486 and 0.2517 which are located on the z-table at 0.67 and 0.68

The given value is closer to 0.2486 so use 0.67 as the z-score.

Now, let's find the x-value using the formula: $z=\dfrac{x-\mu}{\sigma}$

$-0.67=\dfrac{x-20}{6.4}\\\\\\\text{Multiply both sides by 6.4:}\\-4.288=x-20\\\\\\\text{Add 20 to both sides:}\\\large\boxed{15.712} = x$

5 0

3 years ago

Read 2 more answers

This one too! Thank you so much

denis23 [38]

$2(l+w)=P\ \ \ \ |:2\\\\l+w=\dfrac{P}{2}\ \ \ \ \ |-l\\\\\boxed{w=\dfrac{P}{2}-l}$

8 0

3 years ago