Range is just input the domain
so find f(-2), f(0) and f(2)
f(-2)=-(-2)²+1=-4+1=-3
f(0)=-(0)²+1=0+1=1
f(2)=-(2)²+1=-4+1=-3
range={-3,1}
Answer:
x = 4
Step-by-step explanation:
When a tangent and a secant are drawn from an external point to a circle.
Then the product of the external part of the secant and the entire secant and the square of the measure of the tangent are equal, hence
x(x + 5) = 6²
x² + 5x = 36 ( subtract 36 from both sides )
x² + 5x - 36 = 0 ← in standard form
(x + 9)(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 9 = 0 ⇒ x = - 9
x - 4 = 0 ⇒ x = 4
However, x > 0 ⇒ x = 4
Answer:
Step-by-step explanation:
Since the hyperbola opens left and right with a center at the origin, then
In the graph a = 60 and b = 11
So
.
Answer:
1/2x plus -2
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Given the quadratic
d = - 16t² + 12t ← subtract d from both sides
- 16t² + 12t - d = 0 ← in standard form
with a = - 16, b = 12, c = - d
Use the quadratic formula to solve for t
t = ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 4
) / - 32
= 
± 
= 
± 
= ± 
→ D
