Answer:
Small box weighs 13.75 kg & large box weighs 15.75 kg
Step-by-step explanation:
We can write 2 simultaneous equation and solve for weight of each box.
<em>Let weight of large box be l and small box be s.</em>
<em />
"<u>3 large boxes and 5 small boxes has a total weight of 116 kilograms</u>":

and
"<u>9 large boxes and 7 small boxes has a total weight of 238 kilograms</u>":

<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>
<em>
</em>
<em>now,</em>
<em>
</em>
<em />
<em>now we plug in 13.75 into s into equation of l to find s:</em>
<em>
</em>
Answer:y= -4
Step-by-step explanation:
1 Solve for xx in 7x-4y=-127x−4y=−12.
x=\frac{4(y-3)}{7}
x=
7
4(y−3)
2 Substitute x=\frac{4(y-3)}{7}x=
7
4(y−3)
into 9x-4y=-209x−4y=−20.
\frac{36(y-3)}{7}-4y=-20
7
36(y−3)
−4y=−20
3 Solve for yy in \frac{36(y-3)}{7}-4y=-20
7
36(y−3)
−4y=−20.
y=-4
y=−4
4 Substitute y=-4y=−4 into x=\frac{4(y-3)}{7}x=
7
4(y−3)
.
x=-4
x=−4
5 Therefore,
\begin{aligned}&x=-4\\&y=-4\end{aligned}
x=−4
y=−4
A=6a^2
A=6(5.5)^2
A=181.5
Hopefully I answered correctly.
Answer:
cosM ≈ 0.3048
Step-by-step explanation:
remember SOH CAH TOA = sine: opposite/hypotenuse; cosine: adjacent/hypotenuse; tangent: opposite/adjacent
cos = CAH
cosM= a / c
cosM = 4.0 / 13.1244
cosM = 0.30477
cosM ≈ 0.3048
Answer:
Math SMH
Step-by-step explanation: