Answer: hole at x = 0, asymptotes at x = -2 and x = -3
<u>Step-by-step explanation:</u>
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x ≠ 0 ---> the x cancels out so this is a hole
x + 2 ≠ 0 ---> x ≠ -2 ---> asymptote at x = -2
x + 3 ≠ 0 ---> x ≠ -3 ---> asymptote at x = -3
Answer:
B
Step-by-step explanation:
Answer:
Quadrant 4
Step-by-step explanation:
The x value is positive so it is either in 1 or 4
The y value is negative so it is either 3 or 4
To meet both conditions, it must be 4