Answer:
x = 5 and x = -19
Step-by-step explanation:
You're on the right track. It's the "discriminant" that tells you what you want to know here. Before starting, arrange the terms of your quadratic in descending orders of x: 5x^2 + 14x - 19 = 0 (Note that I assumed you meant 14x instead of just 14).
Then the coefficients of this quadratic are a = 5, b = 14 and c = -19.
You are referring to the "quadratic formula." It states this:
-b ± √(b²-4ac)
x = -----------------------
2a
So, we insert the a, b and c values as indicated above:
-14 ± √( 14² - 4[5][-19] ) -14 ± √(196 - 4[5][-19] ) -14 ± √576
x = ----------------------------------- = ---------------------------------- = ----------------------
2(10) 20 20
This comes out to:
x = (-14 + 24) / 2 and x = (-14 - 24) / 2
or:
x = 5 and x = -19
Answer:
10 hours
Step-by-step explanation:
4 times 3 =12 -2= 10
Answer:
Step-by-step explanation:
First we need to set this ratio up in the coordinate plane. Because this is tangent, the 3 goes opposite the reference angle and the 4 goes along the x-axis, adjacent to the reference angle. We see that we are missing the third side of the triangle when we do this, namely the hypotenuse. We use Pythagorean's Theorem to find that this side is 5. Now we have to deal with the identities for each sin(2A) and cos(2A).
sin(2A) = 2sin(A)cos(A)
We know from the triangle we drew in the coordinate plane that
and 
so we fill in the formula accordingly and then simplify:
cos(2A) has 3 identities; I just picked the one I thought would be easiest to use and went with that one. Regardless of which one you pick you will get the same answer as long as you do the math correctly.
and filling in the formula:
I'm not sure why you have 7/2 there...
Answer:
there's an app called mathpapa and if you type in the equation it should answer it for you. or just go to the website. that's how I got passed algebra. GEOMETRY is hard
A, C, E
B false because triangle is confirmed larger if the circle is fit inside of it.
D false because circle on the inside.
A true because triangle on outside
C true because it is a property of inscribed/circumscribed circles/triangles
E true because of inverse relationship
