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Grace [21]
2 years ago
10

I mark brainliest!!!!

Physics
1 answer:
densk [106]2 years ago
6 0

Answer:

I think it is False.

Explanation:

I think that a body could not be vertical for every time.

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Ava runs track and field and is a long-distance runner. She has a big race coming up and needs to eat food that will provide her
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A salad most likely
4 0
3 years ago
Read 2 more answers
The ms = 0.5645 and mk=0.1113 for a 30 N box on level ground. What level force is needed to start the box moving
nevsk [136]

Answer:

16.935 N

Explanation:

In order to make the box start moving, the level force applied on the box (F) must be greater than the force of static friction that keeps the box at rest, which is equal to

F_f = \mu_s (mg)

where

\mu_s = 0.5645 is the coefficient of static friction

(mg) = 30 N is the weight of the box

Therefore, the condition for F must be:

F \geq F_f\\F \geq \mu_k (mg)=(0.5645)(30 N)=16.935 N

So, the applied force must be greater than this value.

3 0
3 years ago
You want to put a new CD in your car stereo.While driving at 45 mi/h,you look away for 2.0s.What distance (in miles) do you driv
KengaRu [80]

Answer:

You drive 0.025 miles blind (or 132 ft)

Explanation:

(distance) = (speed) x (time)

(distance blind) = (speed) x (time looking for CD)

(distance blind) = (45 mi/hr) x (2 s) x (1/3600 hr/s) = 0.025 miles = 132 ft


3 0
3 years ago
Back<br> 8<br> 8.<br> 9.<br> 10.<br> 11.<br> 12.<br> 13.<br> 13
deff fn [24]

Answer:

i dont know the answer for this question sorry for the misunderstanding

Explanation:

3 0
2 years ago
Write an email to a classmate explaining why the velocity of the current in a river has no FN C02-F20-OP11USB effect on the time
anzhelika [568]

The velocity of the current in a river has no effect on the the time it takes to paddle a canoe across the river, given that the boat is pointed perpendicular to the bank of the river, because

The velocity of the river does not change the velocity and therefore the distance traveled in the direction of the boat which is directed perpendicular to it

Reason:

Let \overset \rightarrow {v_y} represent the velocity of the boat across the river in the direction, \overset \rightarrow {d_y}, and let, \overset \rightarrow {v_x}, represent the velocity of the river, we have;

The velocity of the boat perpendicular to the direction of the river = \overset \rightarrow {v_y}

Therefore, the distance covered per unit time in the perpendicular direction

to the flow of the river is \overset \rightarrow {v_y}, such that the time it takes to cross the river in

the perpendicular direction is the same, for every value of the velocity of

the river.

This is so because the velocity in the perpendicular direction to the flow of

the river, which is the velocity of the boat is unchanged by the velocity of

the river, because there is no perpendicular component of velocity in the

velocity of the river.

\overset \rightarrow {v_y} = 3 m/s

\overset \rightarrow {v_x} = 4 m/s

The width of the river, w_y = 6 meters, we have;

  • The resultant velocity = \sqrt{(3 \ m/s)^2 + (4 \ m/s)^2} =5 \ m/s

The direction, θ, is given as follows;

\theta = \arctan \left(\dfrac{4}{3} \right) \approx 53.13^{\circ}

The length of the path of the boat, <em>l</em>, is given as follows;

l = \dfrac{6}{cos \left(\arctan \left(\dfrac{4}{3} \right)\right)} = 10

The length of the path the boat takes = 10 m

The time it takes to cross the river, t = \dfrac{l}{v}, therefore;

  • t = \dfrac{10}{5} = 2
  • The time it takes to cross the river, t = 2 seconds

Considering only the y-components, we have;

t = \dfrac{w_y}{v_y}

Therefore;

t = \dfrac{6 \ m}{3 \ m/s} = 2 \, s

Which expresses that the time taken is the same and given that the

vectors of the velocities of the river and the boat are perpendicular, the

distance covered in the direction of the boat is unaffected by the velocity

of the river.

Learn more vectors here:

brainly.com/question/15907242

5 0
2 years ago
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