Question

Find the inversewill mark brainliest​

Answer 1

Answer:

dat person right

Step-by-step explanation:

Answer 2

Answer:

$f^{-1} (x) = \sqrt[3]{\frac{1 - 9x^{2} }{x^{2} } }$

Step-by-step explanation:

Let f(x) = y

Interchange x and y so

$x = \frac{1}{\sqrt{y^{3} + 9 } }$

$x\sqrt{y^{3} + 9} = 1$

$\sqrt{y^{3} + 9 } = \frac{1}{x}$

$y^{3} + 9 = \frac{1}{x^{2} }$

$y^{3} = \frac{1}{x^{2} } - 9$ = $\frac{1 - 9x^{2} }{x^{2} }$

$y = \sqrt[3]{\frac{1 - 9x^{2} }{x^{2} } }$

$f^{-1} (x) = \sqrt[3]{\frac{1 - 9x^{2} }{x^{2} } }$