Let a,b,c,d and e are five numbers
mean = (a +b+ c+ d+e)/5 = 30
⇒ (a +b+ c+ d+e) = 150_______(1)
now, Let the number excluded be a
then, new mean = (b+ c+ d+e)/4 = 28
⇒ (b+ c+ d+e)= 112
putting this value in (1),
⇒a + 112 = 150
⇒a = 150 -112 = 38
excluded number = 38
The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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Answer:
Step-by-step explanation:
4
Sketch a right
triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x”
and assigning angle “a” as the angle between A and H. Using Pythagorean theorem,
you will get “square root of x-squared minus 9” as the opposite side (O). Using
SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) =
x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side
over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the
algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.
