The rules are


Let me show you why with a couple of examples: suppose we want to multiply

Since powers are just repeated multiplications, we have

Similarly, we have

Answer:
A=ε*l*c
A= 2- log₁₀ % T
Step-by-step explanation:
There is a linear relationship between the concentration of a sample and absorbance according to Beer-Lambert Law.
A=ε*l*c
where;
A=absorbance
ε=absorption coefficient
l=path length
c=concentration
Because % transmittance is transmittance value multiplied by 100 then, the equation that will allow us calculate absorbance from % transmittance value will be;
A= 2- log₁₀ % T where T is transmittance.
Answer:
a. This data best fits an exponential model.
b. The regression equation would be: y = 8385(1.12)^x
c. The y-intercept would be the starting value of the account.
d. Yes, the correlation coefficient is 0.9983.
e. If you input 6 into the equation, you will get a value of $16,550.
Step-by-step explanation:
I hope this helps, and I would appreciate the brainiest asap.
<span>5*s-(4*s)-(1/2) = -1/4-(4/8) // + -1/4-(4/8)
5*s-(4*s)-(1/2)-(-1/4)+4/8 = 0
5*s-4*s-1/2+1/4+4/8 = 0
s+1/4 = 0 // - 1/4
s = -1/4
s = -1/4
</span>