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MrRissso [65]
3 years ago
12

PLEASE HELP I GIVE ALL MY POINTS PLZZZZ!!!!! Select the correct answer. Vector u has its initial point at (1, -12) and its termi

nal point at (18,6). Vector v points in a direction opposite that of u, and its magnitude is three times the magnitude of u. What is the component form of vector V? OA. v=(-51, -54) O B. v=(-51, 18) Ocv=(51, -54) OD. v = (51, -18)​
Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:

Vector u has u_x = (5 - 15) = -10, and u_y = -4 - 22 = -26, and its component form would be u = -10i - 26j.

If vector v is in the opposite direction: 10i + 26j

And if it is double in magnitude: v = 20i + 52j

Hope this helps you! Ask me anything if yu have any quistions!

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Work Shown:

The y coordinate stays the same. Only the x coordinate will change.

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1) The domain is [0,300]. The range is [0,250]

2) The slope for the initial climb is 3.57. The equation of the line is y=3.57 x

3) The rate of change of the second hill is -1.4

4) The rate of change of the third hill is -2.1

5) The blue hill is steeper

6) It is not a function

Step-by-step explanation:

1)

The domain of a function is the set of values of x (the input) for which the function itself is defined.

Instead, the range of a function is the set of values of y (the output) that the function can take.

To find the domain, we have to look at the x-axis and see for which values of x the function is defined. By looking at the graph, we see that the function is defined between

x = 0 and x = 300

So, the domain is [0,300].

To find the range, we have to look at the y-axis and see for which values of y the function has an output. By looking at the graph, we see that the function has values of y between

y = 0 and x = 250

So, the range is [0,250].

2)

The slope of a function in a certain range is given by

m=\frac{\Delta y}{\Delta x}

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\Delta y is the change in the y-coordinate

\Delta x is the change in the x-coordinate

For the initial climb (pink line), we have:

\Delta y = 250 - 0 = 250\\\Delta x = 70 - 0 = 70

Therefore, the slope in this part is

m=\frac{250}{70}=3.57

We can now write the equation of the line in the form

y = mx + b

where b is the y-intercept: since it is zero, the line has simply the form

y=mx \rightarrow y = 3.57 x

3)

Again, to calculate the slope of the hill, we use:

m=\frac{\Delta y}{\Delta x}

where

\Delta y is the change in the y-coordinate

\Delta x is the change in the x-coordinate

For the green hill, we have:

\Delta y = 60-200 = -140

\Delta x = 300-200 = 100

So the rate of change is

m=\frac{-140}{100}=-1.4

4)

As before, the rate of change of the hill is

m=\frac{\Delta y}{\Delta x}

For the blue hill, we have:

\Delta y = 30-230 = -300

\Delta x = 200-60 = 140

So the rate of change is

m=\frac{-300}{140}=-2.1

5)

To know which hill is steeper, we need to compare the magnitude of their rate of change.

In fact, both hills have rate of change negative - because we are going down along the slope. Therefore, we have to consider the magnitude of their slope.

For the green hill:

|m| = 1.4

For the blue hill:

|m|=2.1

We see that the blue hill has a greater slope (in magnitude): therefore, the blue hill is steeper.

6)

A function is defined as a mapping (operation between two sets of variables) in which to one value of x (the input) corresponds one and only one value of y (the output).

This means that a function cannot have multiple values of y for the same x (the input).

By looking at the graph, we see that this function does not respect this criterium: in fact, we see that certain values of x give multiple values of the output, y (for instance, at x=300 the function has two values). So, this is not a function.

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