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hammer [34]
2 years ago
13

LOGARITHMIC functions have 2 asymptotes True False

Mathematics
1 answer:
JulsSmile [24]2 years ago
8 0

true, both have a domain limited to x values great then 0

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Determine the slope of the line that passes through the points (9, -3) and (-9, -6).
vlabodo [156]

The slope of the line would be 1/6x

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2 years ago
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What is the value of 9 in 309.15​
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The answer is tens because all the numbers the decimal end with an ‘s’, and all the numbers the decimal end with a ‘ths’.
4 0
3 years ago
Hi can someone PLEASE explain this to me i’m STRUGGLING
faltersainse [42]

Answer:

x = 80

Step-by-step explanation:

In a quadrilatoral the interior angle sum always adds up to 360 degrees so to find x you would add all of the interior angle sums and subtract that from 360

115 + 95 + 70 + x = 360     just add the like terms

280 + x = 360                 now subtract 280 from both sides so x is alone and you can figure out its value

x= 80

4 0
3 years ago
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PLEASE HELP!! WILL MARK BRAINIEST !!
SOVA2 [1]

Answer:

(f+g)(2) = 10

Step-by-step explanation:

f(x)=2x^2+3x

g(x)=x-2

(f+g)(x) will be sum of f(x) and g(x)

(f+g)(x)  = 2x^2+3x + x - 2 = 2x^2+4x - 2

we have to find  (f+g)(2), for that we will put x = 2

(f+g)(x)  = 2x^2+4x - 2

(f+g)(2)  = 2*2^2+2*2 - 2\\(f+g)(2)  = 2*4+4 - 2\\(f+g)(2)  = 8+4 - 2 = 10

Thus,  (f+g)(2) is 10.

3 0
2 years ago
Noise levels at 5 airports were measured in decibels yielding the following data: 152,154,139,124,120 Construct the 80% confiden
Yuri [45]

Answer:

137.8-1.533\frac{15.595}{\sqrt{5}}=127.108    

137.8+1.533\frac{15.595}{\sqrt{5}}=148.492    

So on this case the 80% confidence interval would be given by (127.108;148.492)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=137.8

The sample deviation calculated s=15.595

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,4)".And we see that t_{\alpha/2}=1.533

Now we have everything in order to replace into formula (1):

137.8-1.533\frac{15.595}{\sqrt{5}}=127.108    

137.8+1.533\frac{15.595}{\sqrt{5}}=148.492    

So on this case the 80% confidence interval would be given by (127.108;148.492)    

5 0
3 years ago
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