LOGARITHMIC functions have 2 asymptotes<br> True<br> False

In a quadrilatoral the interior angle sum always adds up to 360 degrees so to find x you would add all of the interior angle sums and subtract that from 360

115 + 95 + 70 + x = 360 just add the like terms

280 + x = 360 now subtract 280 from both sides so x is alone and you can figure out its value

x= 80

4 0

3 years ago

Read 2 more answers

PLEASE HELP!! WILL MARK BRAINIEST !!

SOVA2 [1]

Answer:

(f+g)(2) = 10

Step-by-step explanation:

f(x)=2x^2+3x

g(x)=x-2

(f+g)(x) will be sum of f(x) and g(x)

(f+g)(x) = 2x^2+3x + x - 2 = 2x^2+4x - 2

we have to find (f+g)(2), for that we will put x = 2

(f+g)(x) = 2x^2+4x - 2

$(f+g)(2) = 2*2^2+2*2 - 2\\(f+g)(2) = 2*4+4 - 2\\(f+g)(2) = 8+4 - 2 = 10$

Thus, (f+g)(2) is 10.

3 0

2 years ago

Noise levels at 5 airports were measured in decibels yielding the following data: 152,154,139,124,120 Construct the 80% confiden

Yuri [45]

Answer:

$137.8-1.533\frac{15.595}{\sqrt{5}}=127.108$

$137.8+1.533\frac{15.595}{\sqrt{5}}=148.492$

So on this case the 80% confidence interval would be given by (127.108;148.492)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=137.8$

The sample deviation calculated $s=15.595$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,4)".And we see that $t_{\alpha/2}=1.533$

Now we have everything in order to replace into formula (1):

$137.8-1.533\frac{15.595}{\sqrt{5}}=127.108$

$137.8+1.533\frac{15.595}{\sqrt{5}}=148.492$

So on this case the 80% confidence interval would be given by (127.108;148.492)

5 0

3 years ago

LOGARITHMIC functions have 2 asymptotes True False