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svet-max [94.6K]
3 years ago
10

PLEASE HELP ILL GIVE BRAINLIEST!!!!

Mathematics
2 answers:
Annette [7]3 years ago
4 0
The last one is correct.
4vir4ik [10]3 years ago
4 0

Answer:

the graph selected

Step-by-step explanation:

If we look to the third graph we can see that all data are concetrated on the left part of the graph, but there is one that is on the right part, so it is an outlier

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Sorry if it is blurry but can you give me the answer plsss
Naya [18.7K]
B. 21 mmmmmmmmmmmmmmmmmmmmmmmm
6 0
3 years ago
Read 2 more answers
Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}
Lady_Fox [76]

Answer:

\mathbf{\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 (e^7 -8)}

Step-by-step explanation:

Given that:

\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end  {bmatrix}\ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  \dfrac{4}{2}[e^y -1]^7_0 \ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 [(e^7 -7)-(e^0 -0)]

\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 [(e^7 -7)-1]

\mathbf{\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 (e^7 -8)}

3 0
4 years ago
Two integers have a sum of 42 and a difference of 22. The greater of the two<br> integers is
DochEvi [55]
Let
x = larger integer
y = smaller integer

The two integers (x and y) have a sum of 42 which means they add to 42

x+y = 42

solve for y to get 

y = 42-x

simply by subtracting x from both sides

---------------------------------------------------

The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,

x-y = 22

Plug in y = 42-x. Solve for x

x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32

If x = 32, then y is...
y = 42-x
y = 42-32
y = 10

Therefore, 
x = 32
y = 10

The final answer is 10

5 0
4 years ago
Read 2 more answers
Re-write the quadratic function below in Standard Form<br> y = -(x + 8)(x + 7)
Iteru [2.4K]

Answer:

y = - x² - 15x - 56

Step-by-step explanation:

y = - (x + 8)(x + 7) ← expand factors using FOIL

  = - (x² + 15x + 56) ← distribute parenthesis by - 1

y = - x² - 15x - 56 ← in standard form

6 0
3 years ago
What are the missing numbers?
inna [77]

Answer:

The first box is 2.089

The second box is 2.095

Step-by-step explanation:

Between each line there is 1 thousandth added to the number.

6 0
3 years ago
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