B. 21 mmmmmmmmmmmmmmmmmmmmmmmm
Answer:

Step-by-step explanation:
Given that:
![\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]](https://tex.z-dn.net/?f=%5Cint%20%5Cint%20_R%204xye%5E%7Bx%5E2%20%5C%20y%7D%20%5C%20dA%2C%20R%20%3D%20%5B0%2C1%5D%5Ctimes%20%5B0%2C7%5D)
The rectangle R = [0,1] × [0,7]
R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }
R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }




![\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy](https://tex.z-dn.net/?f=%5Cint%20%5Cint%20_R%20%5C%204xy%20e%5E%7Bx%5E2%20%5C%20y%7D%20%20%5C%20dA%20%3D%20%20%5Cdfrac%7B4%7D%7B2%7D%5Be%5Ey%20-1%5D%5E7_0%20%5C%20dy)
![\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)]](https://tex.z-dn.net/?f=%5Cint%20%5Cint%20_R%20%5C%204xy%20e%5E%7Bx%5E2%20%5C%20y%7D%20%20%5C%20dA%20%3D%20%202%20%5B%28e%5E7%20-7%29-%28e%5E0%20-0%29%5D)
![\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1]](https://tex.z-dn.net/?f=%5Cint%20%5Cint%20_R%20%5C%204xy%20e%5E%7Bx%5E2%20%5C%20y%7D%20%20%5C%20dA%20%3D%20%202%20%5B%28e%5E7%20-7%29-1%5D)

Let
x = larger integer
y = smaller integer
The two integers (x and y) have a sum of 42 which means they add to 42
x+y = 42
solve for y to get
y = 42-x
simply by subtracting x from both sides
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The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,
x-y = 22
Plug in y = 42-x. Solve for x
x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32
If x = 32, then y is...
y = 42-x
y = 42-32
y = 10
Therefore,
x = 32
y = 10
The final answer is 10
Answer:
y = - x² - 15x - 56
Step-by-step explanation:
y = - (x + 8)(x + 7) ← expand factors using FOIL
= - (x² + 15x + 56) ← distribute parenthesis by - 1
y = - x² - 15x - 56 ← in standard form
Answer:
The first box is 2.089
The second box is 2.095
Step-by-step explanation:
Between each line there is 1 thousandth added to the number.