If f(x) = 2x - 1, find f'(x).

2 answers:

Mumz [18]3 years ago

4 0

Answer:

f'(x)=2

Step-by-step explanation:

$if~y=ax^n\\where~a~is~constant.\\\frac{dy}{dx} =a nx^{n-1}\\f(x)=2x-1\\f'(x)=2*1x^{1-1}-0\\=2x^0\\=2*1\\=2$

Kitty [74]3 years ago

3 0

Answer:f(x)=3

Step-by-step explanation:

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If f(x) = 2x - 1, find f'(x).​