Question

If f(x) = 2x - 1, find f'(x).​

Answer 1

Answer:

f'(x)=2

Step-by-step explanation:

$if~y=ax^n\\where~a~is~constant.\\\frac{dy}{dx} =a nx^{n-1}\\f(x)=2x-1\\f'(x)=2*1x^{1-1}-0\\=2x^0\\=2*1\\=2$

Answer 2

Answer:f(x)=3

Step-by-step explanation: