Which of the following are solutions to the equation below?

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

First simplify then solve.

$4x^2+20x+25=49 \\4x^2+20x-24=0 \\4(x^2+5x-6)=0 \\x^2+5x-6=0\Longrightarrow(x+6)(x-1)=0 \\\boxed{x_1=-6, x_2=1}$

We find there are two solutions. In your case the correct answers are A, C, D

Hope this helps.

r3t40

Hope this helps.

r3t40

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y = 0 (x -axis)

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The attachment below is the graphical solution obtained from desmos graphing tool;

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