The slope of the given linear equation is 1/3 and the y-intercept will be 5/6. Then the correct option is D.
<h3>What is the slope?</h3>
The slope is the ratio of rising or falling and running. The difference between the ordinate is called rise or fall and the difference between the abscissa is called run.
Identify the slope and y-intercept of the line whose equation is given. Write the y-intercept as an ordered pair.
The linear equation is given below.
![\rm y =\dfrac{5}{6} + \dfrac{x}{3}](https://tex.z-dn.net/?f=%5Crm%20%20y%20%3D%5Cdfrac%7B5%7D%7B6%7D%20%2B%20%5Cdfrac%7Bx%7D%7B3%7D)
Then the slope of the equation will be 1/3.
And the y-intercept will be 5/6.
More about the slope link is given below.
brainly.com/question/3605446
#SPJ1
Answer:
20%
Step-by-step explanation:
300 - 240 = 60 ÷ 300 = 20% mangoes.
G(f(x))= (7x+8)^4
g(f(x))= (7(0)+8)^4
=(0+8)^4
=8^4
=8•8•8•8
=4,096
Complete Question
The relationship between altitude and the boiling point is linear. At an altitude of 8300ft, the liquid boils at 194.23 ° F
At an altitude of 4200 ft , the liquid boils at 202.02° F.
Write an equation giving the boiling point b of the liquid, in terms of altitude a in feet . feet . What is the boiling point of the liquid at 2600ft
Answer:
The equation is ![y = -0.001943x + 210.3569](https://tex.z-dn.net/?f=y%20%20%3D%20%20-0.001943x%20%2B%20210.3569%20)
At 2600ft the temperature is ![y = 205.3051 \ °F](https://tex.z-dn.net/?f=y%20%20%3D%20%20205.3051%20%5C%20%20%C2%B0F%20)
Step-by-step explanation:
From the question we are told that
The temperature at 8300ft is 194.23 ° F
The temperature at 4200 ft is 202.02° F
Generally the slope for this relationship is mathematically represented as
![m = \frac{ 202.2 - 194.23}{ 4200 - 8300}](https://tex.z-dn.net/?f=m%20%20%3D%20%20%5Cfrac%7B%20202.2%20-%20194.23%7D%7B%204200%20-%208300%7D)
=>
Generally the according to the point slope formula is
![y - y_1 = m(x -x_1 )](https://tex.z-dn.net/?f=y%20-%20y_1%20%20%3D%20%20m%28x%20-x_1%20%29)
=> ![y - 194.23 = -0.001943 (x - 8300 )](https://tex.z-dn.net/?f=y%20-%20194.23%20%3D%20%20-0.001943%20%28x%20-%208300%20%29)
=> ![y - 194.23 = -0.001943x + 16.1269](https://tex.z-dn.net/?f=y%20-%20194.23%20%3D%20%20-0.001943x%20%2B%2016.1269%20)
=> ![y = -0.001943x + 210.3569](https://tex.z-dn.net/?f=y%20%20%3D%20%20-0.001943x%20%2B%20210.3569%20)
Now we are given from the question that x = 2600 ft
Then
![y = -0.001943(2600) + 210.3569](https://tex.z-dn.net/?f=y%20%20%3D%20%20-0.001943%282600%29%20%2B%20210.3569%20)
=> ![y = 205.3051 \ °F](https://tex.z-dn.net/?f=y%20%20%3D%20%20205.3051%20%5C%20%20%C2%B0F%20)
You would multiply the two terms which are -6y^2 and -13x^2*y^5.
Multiplying -6 by -13 yields 78, which will be the new coefficient.
Since there is only the x^2 from the second term, that remains the same. However, there are two y values that we can multiply together: y^2 and y^5. y^2 * y^5 = y^(2 + 5) = y^7.
Therefore, your answer is 78x^2*y^7.