F(3) = 9
f'(3) = 3
L(x) = linear approximation to f(x) at x = a
L(x) = linear approximation to f(x) at x = 3
L(x) = f'(a)*(x-a)+f(a)
L(x) = f'(3)*(x-3)+f(3)
L(x) = 3*(x-3)+9
L(x) = 3x-9+9
L(x) = 3x
L(3.02) = 3*3.02
L(3.02) = 9.06
So f(3.02) is approximately 9.06 based on the L(x) linear approximation
g(9) = 3
g'(9) = 5
M(x) = linear approximation to g(x) at x = 9
M(x) = linear approximation to g(x) at x = a
M(x) = g'(a)*(x-a)+g(a)
M(x) = g'(9)*(x-9)+g(9)
M(x) = 5*(x-9)+3
M(x) = 5x-45+3
M(x) = 5x-42
M(9.06) = 5*9.06-42
M(9.06) = 3.3
So g(9.06) is approximately equal to 3.3 based on the linear approximation M(x)
In summary, this means
g(9.06) = g(f(3.02)) = 3.3
which are approximations
The final answer is 3.3
Answer:
y = -1x - 7
Step-by-step explanation:
y2 - y1 / x2 - x1
-6 - (-3) / -1 - (-4)
-3/3
= -1
y = -1x + b
-6 = -1(-1) + b
-6 = 1 + b
-7 = b
Abscissa - perpendicular distance from the y- axis
ordinate - perpendicular distance from the x- axis
In a point P(x,y)
x is abscissa and y is ordinate
