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2 years ago

In ΔPQR, p = 75 inches, q = 73 inches and r=35 inches. Find the measure of ∠P to the nearest 10th of a degree.

Mathematics

2 answers:

love history [14]2 years ago

5 0

Answer:

cosp = 79.5

Step-by-step explanation:

soldi70 [24.7K]2 years ago

3 0

Answer:

79.5

Step-by-step explanation:

a^2 =b^2+ c^2-2bc cos A

cos p = 73^2+35^2-75^2/2(73)(35)

cos p= 9229/5110

cosp=79.5

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3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

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9 months ago

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Answer:

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2 years ago

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How can I solve for the logarithm?

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$\bf 12^{2x-8}=15\\\\
-----------------------------\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\impliedby thus\\\\
-----------------------------\\\\
log\left( 12^{2x-8} \right)=log(15)\implies (2x-8)log(12)=log(15)
\\\\\\
2x-8=\cfrac{log(15)}{log(12)}\implies 2x=\cfrac{log(15)}{log(12)}+8\implies 
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3 years ago