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3 years ago

Please answer today! Ill give brainlest

Mathematics

1 answer:

inysia [295]3 years ago

8 0

Answer:

16 meters

Step-by-step explanation:

pls give the brainiest

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Celik, S. (2011). A media comparison study on first aid instruction. Health Education Journal. 72(1), 95-101

aniked [119]

Answer:

The answer is "Option a".

Step-by-step explanation:

In the given scenario, The appropriate test for the teaching profession's accomplishment pre and post-class would be the two-sample t-test with dependent samples, that's why choice "a" is correct.

7 0

3 years ago

Please help with 2 questions. Thank you.

8_murik_8 [283]

${e}^{ln(anything)} = anything$

so here we have:

${e}^{ln1} = 1$

${e}^{ln5x} = 5x$

8 0

3 years ago

The athletic departments at 10 randomly selected U.S. universities were asked by the Equal Employment Opportunity Commission to

Lesechka [4]

Answer: Mean = 3.5 , median = 2.5, mode = 2, geometric mean = 2.74

Median is the most appropriate measure of central tendency.

The least appropriate = mean

Yes there is an outlier.

Step-by-step explanation:

Given responses : 5, 4, 2, 1, 1, 2, 10, 2, 3, 5.

First arrange them in increasing order, $\sqrt[10]{1\times1\times2\times2\times2\times3\times4\times5\times5\times10 }\\\\=\sqrt[10]{24000} \approx2.74$

Its sum = 35

Mean of n observations = (Sum of observations) ÷ n

Mean = (35) ÷ 10

=3.5

Here n =10 (even)

Median = average of middle most numbers = $\dfrac{2+3}{2}=\dfrac52=2.5$

Mode = most repeated number = 2 (thrice)

geometric mean = $\sqrt[n]{x_1\times x_2\times.... x_n}$

10 is an outlier as it is very large as compare to other numbers.

When outlier is present in data , the median is the most appropriate measure of central tendency.

Mean affected badly by the outlier so it the least appropriate.

4 0

3 years ago

The curve with equation y=e^2x/4+3e^x has one stationary point.find the exact value of the coordinates of this point

Softa [21]

$y=\dfrac{e^{2x}}{4+3e^x}$
$\implies y'=\dfrac{2e^{2x}(4+3e^x)-3e^xe^{2x}}{(4+3e^x)^2}$
$\implies y'=\dfrac{8e^{2x}+3e^{3x}}{(4+3e^x)^2}$

Stationary points occur where the derivative is zero. The denominator is positive for all $x$ , so we only need to worry about the numerator.

$8e^{2x}+3e^{3x}=e^{2x}(8+3e^x)=0$

$e^{2x}>0$ for all $x$ , so we can divide through:

$8+3e^x=0\implies e^x=-\dfrac83$

But $e^x>0$ for all $x\in\mathbb R$ , so this function has no stationary points...

I suspect there may be a typo in the question.

6 0

3 years ago

How do you solve quadratic equations?

masha68 [24]

In any equation there is a variable (usually x). In a quadratic equation there is a lot involved.

-B (+or-) sqrt of b^2 - 4 x A x C
________________________ divide it by
2 x A
There is usually an original equation that looks like: Ax^2 + Bx + C = 0 Use the variables from the equation to the left to fill the upper equation. (You can also look up a better formula if confused).

8 0

3 years ago