How do you do this question?
2 answers:
Answer:
B
Step-by-step explanation:
f(x) = sin^2(3 - x)
f'(x) = 2*sin(3 - x)*cos(3 - x)(-1)
This comes from d(sin^2(3 - x))/dx which is 2*sin^2(3 - x)
d(sin(3 - x)/dx which is cos(3 - x)
d(3 - x) = - 1
f'(0) = (-1) * 2*sin(3)*cos(3)
Looks like B
Answer:
Step-by-step explanation:

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