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IgorC [24]
3 years ago
11

NEED HELP PLEASE as soon as possible!!!

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

b 0.33333333333333333

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I am giving a brainliest to the best answer
arsen [322]

Answer:

A

Step-by-step explanation:

Given

f(x) = \frac{x+3}{4}

let f(x) = y and rearrange making x the subject

y = \frac{x+3}{4} ( multiply both sides by 4 )

4y = x + 3 ( subtract 3 from both sides )

4y - 3 = x

Change y back into terms of x

f^{-1}(x) = 4x - 3 → A

3 0
3 years ago
How to tell if the shape on a dot plot is symmetric or not symmetric
RUDIKE [14]
Idk if this helped you but , symmetric forms a mirror image of itself when reflected in its vertical line ( u shape ) and symmetric bell shaped is when you draw the vertical line at the center
7 0
3 years ago
In the figure, the ratio of the perimeter of rectangle ABDE to the perimeter of triangle BCD is 2/3 1 3/2 2 . The area of polygo
adelina 88 [10]
It would b 2/3 and the other one 2/4

6 0
3 years ago
The stream of water from a fountain follows a parabolic path. The stream reaches a maximum height of 7 feet, represented by a ve
xenn [34]

First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.

If we need the vertex to be at x=4, the equation will contain a (x-4)^2 term.

If we start with y=-(x-4)^2 we have a parabola, concave down, with vertex at x=4 and a maximum of 0.

So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be (4, 7)

We have

y = -(x-4)+7

Now we only have to fix the fact that this parabola doesn't land at (8,0), because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

y = a(x-4)^2+7

such that:

  • a
  • when we plug x=8, we have y=0

Plugging these values gets us

0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}

As you can see in the attached figure, the parabola we get satisfies all the requests.

3 0
3 years ago
Write 46 over 74 in simplest form
deff fn [24]
\hbox{The GCF \rightarrow2}

\frac{46\div2}{74\div2}  \\  \\ \bold {\boxed{{\pmb{ \frac{23}{37} }}}}
3 0
3 years ago
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