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Schach [20]
3 years ago
13

\dfrac k{2}+\dfrac12=3 2 k ​ + 2 1 ​ =3

Mathematics
2 answers:
Lorico [155]3 years ago
7 0

Answer:

it 5

Step-by-step explanation:

i got i correct

konstantin123 [22]3 years ago
3 0

it's so hard to find it

Step-by-step explanation:

I didn't know

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Find the amount withheld for Social Security weekly:
stira [4]

The amount withheld for Social Security weekly: $21.70.

<h3>Social security</h3>

Social security rate is 6.2% or 0.062

Weekly salary=$350

Using this formula

Social security=Social security rate×Weekly salary

Let plug in the formula

Social security=0.062×$350

Social security=$21.70

Therefore the amount withheld for Social Security weekly: $21.70.

Learn more about Social security here:brainly.com/question/1156607

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7 0
2 years ago
Variables x and y are in direct proportion, and y = 48n when x = 16n. Which value of k correctly relates x and y in the equation
ella [17]
You want k.
k=y/x=48n/16n=3
3 0
3 years ago
The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation
Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

  • Sample size: n = 20
  • Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}    

This gives

P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}

P(x = 11) = 0.0011

Express as percentage

P(x = 11) = 0.11\%

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all  20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}    

This gives

P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0

P(x = 20) = 0.0388

Express as percentage

P(x = 20) = 3.88\%

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

\mu = np

So, we have:

\mu = 20 \times 85\%

\mu = 17

The standard deviation is calculated as:

\sigma = np(1 - p)

So, we have:

\sigma = 20 \times 85\% \times (1 - 85\%)

\sigma = 20 \times 0.85 \times 0.15

\sigma = 2.55

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0
3 years ago
3. There are 45 males and 60 females in a subway car. What is the ratio of males to females? Write your answer as a fraction in
Studentka2010 [4]

Answer:

3/4 or 0.75

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Which expression is equivalent to ^4sqrt6/^3sqrt2?
BigorU [14]

\dfrac{\sqrt[4]6}{\sqrt[3]2}=6^\frac{1}{4}:2^\frac{1}{3}=6^\frac{1\cdot3}{4\cdot3}:2^{\frac{1\cdot4}{3\cdot4}}=6^\frac{3}{12}:2^\frac{4}{12}=(6^3)^\frac{1}{12}:(2^4)^\frac{1}{12}\\\\=216^\frac{1}{12}:16^\frac{1}{12}=(216:16)^\frac{1}{12}=\sqrt[12]{\dfrac{216}{16}}=\sqrt[12]{\dfrac{27}{2}}\\\\\text{Answer:}\ 1)\ \sqrt[12]{\dfrac{27}{2}}

4 0
3 years ago
Read 2 more answers
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