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NISA [10]
3 years ago
6

Determine the area of the figure shown. Note that each square unit is one unite in length

Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

74 units squared

Step-by-step explanation:

we know that the area of a square or rectangle is A = L × w

so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.

so I'll start with the middle square its length is 8 and width is 8 too.

A = 8 × 8

A = 64

now we'll move on to the other small ones to the side.

the one on the right side it's length is 2 and width is 2.

A = 2 × 2

A = 4

and then the last one on the left, Length is 3, width is 2.

A = 2 × 3

A = 6

now we'll add up all of the areas to get the total area.

Total = 64 + 4 + 6

Total = 74 units squared

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atroni [7]

Answer:

18.75m³ of sand

Step-by-step explanation:

volume =lbh

h=125cm=1.25m

v=2.4*6.25*1.25

=18.75m³

7 0
3 years ago
5(10k+1)+2(2+8k) simplify
iVinArrow [24]
Firstly expand it: 50k + 5 + 4 + 16k
Collect like terms: (50k + 16K) + (5 + 4)
Simplify: 66k + 9.
4 0
3 years ago
Greyhounds can reach speeds of 20.1 meters per second. Which conversion factor can be used to find this speed in meters per minu
kicyunya [14]

Answer:

Step-by-step explanation:

20.1metres / seconds

We want to convert to metres /minutes

It is known that 60seconds=1minutes

So therefore, either we multiply 20.1metres/seconds by

60seconds/1minutes

Or

1minutes/60seconds

Multiplying with the above does not change the magnitude of the quantity because it is like we are multiplying by 1.

Since we want to cancel seconds and it is in the denominator, so to do this we need to multiply with the fraction that has the seconds as numerator.

So, we are going to multiply with 60seconds/1minutes

20.1metres/seconds ×60seconds/minutes

1206metres/minutes.

So the correct fraction is the StartFraction 60 seconds Over 1 minute, which is the third option

7 0
2 years ago
Read 2 more answers
10
Novay_Z [31]

Answer:

The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎

Step-by-step explanation:

For a reflection across the line y = -x, we have, (x, y) → (y, x)

Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x

The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)

Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'

Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎

5 0
2 years ago
Том и Эми установили будильники на своих телефонах на 6:45. Оба сигнала тревоги звучат одновременно в 6.45. Будильник Тома звучи
Debora [2.8K]

Answer:

36 минут спустя в 7:21

это проблема LCM, поэтому вот как ее решить.

Том звучит через 9, 18, 27, 36 минут после первоначального звучания.

Звуки Эми в 12, 24, 36 минут

Итак, в 7:21, через 36 минут после того, как они ушли, и Том, и Эми проснулись, и они оба опоздали.

-------------------

Translation

36 minutes later at 7:21am

this is a LCM problem so this how to solve it.

Toms sounds at 9, 18, 27, 36 minutes after it initially sounds

Amy’s sounds at 12, 24, 36 minutes

so at 721am 36 minutes after they went off both Tom and Amy when they woken up,they were both late.

8 0
2 years ago
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