The answer is 36in because that’s the pathagreom you need to use to find the answer
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
N is greater than or equal to 11, I believe
Answer:
20,158 cases
Step-by-step explanation:
Let 
represent year 2010.
We have been given that since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year.
Since the flu cases decrease to 85% of the prior year, so the flu cases for every next year will be 85% of last year and decay rate is 15%.
We can represent this information in an exponential decay function as:
To find number of cases in 2020, we will substitute 
in our decay function as:
Therefore, 20,158 cases will be reported in 2020.
Answer:
the answer is of the question is 216
