We are given dimensions of model and actual figure.
model: 9.5cm actual : 30.5m.
We need to find the length of actual shape for the scale factor 5cm.
Let us assume actual length be x m.
Let us set a proportion now.
<h3>5 : x = 9.5 : 30.5</h3>
Let us convert proportion into fractions.

On cross multiplying, we get
9.5x = 5× 30.5
9.5x = 152.5.
On dividing both sides by 9.5, we get

x=16.05.
<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>
Step-by-step explanation: To find the volume of a sphere, start with the formula for the volume of a sphere which is shown below.

Here, we are given that our sphere has a radius of 4 units.
So plugging into the formula, we have
.
Start by simplifying the exponent.
(4 units)³ is equal to (4 units) (4 units) (4 units) or 64 units³.
So we have
.
Next, we multiply (4/3)(64) which can
be thought of as (4/3)(64/1)
So multiplying across the numerators and across the denominators,
we have
.
Answer:
- perimter of original rectangle = <u>17. 6 mm</u>
- side length of the enlarged rectangle = <u>23. 22 mm</u>
- perimeter of the enlarged rectangle = <u>95. 04 mm</u>
Step-by-step explanation:
<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>
- Length of original rectangle = 4.5 mm
- Width of original rectangle = 4.3 mm
<em>perimeter = 2 × ( length + width)</em>
= 2 × ( 4.5 + 4.3)
= 2 × 8.8
= 17. 6 mm
<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>
- Width of original rectangle = 4. 5 mm
- Width of enlarged rectangle = 24.3 mm
Enlargement factor = 24.3 / 4.5
= 5.4
- Length of original rectangle = 4.5 mm
- Enlargement factor = 5.4
Side length of enlarged rectangle
= original length × Enlargement factor
= 4.3 × 5.4
= 23. 22 mm
<u>PERIMTER OF ENLARGED RECTANGLE</u>
= 2 × ( enlarged ength + enlarged breadth)
= 2 × (23. 22 + 24. 3 )
= 95. 04 mm
First you find 4/5 of 8 and then 4/5of 7 and multiply them
Answer:
The distance between the astronomers and the moon was
meters.
Step-by-step explanation:
We have that the speed is the distance divided by the time, so:

In this problem, we have that:
The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that
.
If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?
We have that
m/s.
We have to find d. So:



![7.56*10^{8]](https://tex.z-dn.net/?f=7.56%2A10%5E%7B8%5D)
The distance between the astronomers and the moon was
meters.