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aniked [119]
3 years ago
10

PLEASE HELP mE: Simplify the expression 5c - 4 + 2c +6

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

7c+2

Step-by-step explanation:

Hope this helps!

Brain-List?

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The scale factor for a model is 5cm= m model: 9.5cm actual : 30.5m
MaRussiya [10]

We are given dimensions of model and actual figure.

model: 9.5cm actual : 30.5m.

We need to find the length of actual shape for the scale factor 5cm.

Let us assume actual length be x m.

Let us set a proportion now.

<h3>5 : x = 9.5 : 30.5</h3>

Let us convert proportion into fractions.

\frac{5}{x}=\frac{9.5}{30.5}

On cross multiplying, we get

9.5x = 5× 30.5

9.5x = 152.5.

On dividing both sides by 9.5, we get

\frac{9.5x}{9.5}=\frac{152.5}{9.5}

x=16.05.

<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>

6 0
4 years ago
What is the volume of a sphere with a radius of 4
Ede4ka [16]

Step-by-step explanation: To find the volume of a sphere, start with the formula for the volume of a sphere which is shown below.

V = \frac{4}{3}\pi  r^{3}

Here, we are given that our sphere has a radius of 4 units.

So plugging into the formula, we have (\frac{4}{3})(\pi)(4 units)^{3}.

Start by simplifying the exponent.

(4 units)³ is equal to (4 units) (4 units) (4 units) or 64 units³.

So we have (\frac{4}{3})(\pi)(64 units^3}).

Next, we multiply (4/3)(64) which can

be thought of as (4/3)(64/1)

So multiplying across the numerators and across the denominators,

we have \frac{256}{3} \pi units^{3}.

5 0
3 years ago
The perimeter of the original rectangle is ______
sergey [27]

Answer:

  • perimter of original rectangle = <u>17. 6 mm</u>
  • side length of the enlarged rectangle = <u>23. 22 mm</u>
  • perimeter of the enlarged rectangle = <u>95. 04 mm</u>

Step-by-step explanation:

<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>

  • Length of original rectangle = 4.5 mm
  • Width of original rectangle = 4.3 mm

<em>perimeter = 2 × ( length + width)</em>

= 2 × ( 4.5 + 4.3)

= 2 × 8.8

= 17. 6 mm

<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>

  • Width of original rectangle = 4. 5 mm
  • Width of enlarged rectangle = 24.3 mm

Enlargement factor = 24.3 / 4.5

= 5.4

  • Length of original rectangle = 4.5 mm
  • Enlargement factor = 5.4

Side length of enlarged rectangle

= original length × Enlargement factor

= 4.3 × 5.4

= 23. 22 mm

<u>PERIMTER OF ENLARGED RECTANGLE</u>

= 2 × ( enlarged ength + enlarged breadth)

= 2 × (23. 22 + 24. 3 )

= 95. 04 mm

8 0
3 years ago
Which shows how the distributive property can be used to evaluate 7×8 4/5
Greeley [361]
First you find 4/5 of 8 and then 4/5of 7 and multiply them
5 0
3 years ago
Read 2 more answers
During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be
rusak2 [61]

Answer:

The distance between the astronomers and the moon was 7.56*10^{8] meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

v = \frac{d}{t}

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that t = 2.52.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that v = 3*10^{8}m/s.

We have to find d. So:

v = \frac{d}{t}

d = vt

d = 3*10^{8}*2.52

7.56*10^{8]

The distance between the astronomers and the moon was 7.56*10^{8] meters.

7 0
4 years ago
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