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Minchanka [31]
3 years ago
12

What are expressions that are equivalent to -4/3p - 2/5?

Mathematics
1 answer:
slega [8]3 years ago
3 0

-4/3 - 2/5

HOPE THAT HELPS DUDE

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If (a+b)(a-b)=21,a+b=7 and a-b=3 what Is the value of a
topjm [15]

9514 1404 393

Answer:

  5

Step-by-step explanation:

Add the latter two equations and you get ...

  (a +b) +(a -b) = (7) +(3)

  2a = 10 . . . . . . . . . . . . . . . simplify

  a = 5 . . . . . . . divide by 2

8 0
3 years ago
Help please help please
xxTIMURxx [149]

Answer:

Combine like terms

Step-by-step explanation:

The first step in such equations is to simplify the equation which is done most often by combining like terms, and by combining like terms i mean for example:

1 + 5 + 3x = 4y + z

You will combine the like terms (those that can be added or subtracted):

6 + 3x = 4y + z

In our example, combining terms would be adding 2x/3 and 1x/3 to give

3x/3 + 2 = 5

The equation is now simple and easy to solve as you simplify 3x/3 to 1x and then proceed to rearrange the equation to yield the value of x

Hope this helps!

6 0
3 years ago
Divid 15 into two parts such that the sum of their reciprocal is 3/10
emmasim [6.3K]
Let x and y be the 2 parts of 15 ==> x + y=15 (given)

Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)


Let's solve  1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)

 ==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy

But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50

Now we have the sum S of the 2 parts that is S = 15 and 
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
4 0
3 years ago
HELP ME PLEASE ASAP?!?What is the value of y?
Snezhnost [94]
Answer: y = 57°

Explanation: 180-114 = 66°

A triangle has a total of 180° so 180-66 = 114

114 / 2 = 57° (because angles y and y have the same value)

Hope this helps :)
7 0
3 years ago
A = √7 + √c and b = √63 + √d where c and d are positive integers.
mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]

b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]

From [3]:

9c=d

Replacing into [2]:

b=\sqrt{63}+\sqrt{9c}

We can express 63=9*7:

b=\sqrt{9*7}+\sqrt{9c}

Taking the square root of 9:

b=3\sqrt{7}+3\sqrt{c}

Factoring:

b=3(\sqrt{7}+\sqrt{c})

Find the ration a:b:

\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}

Simplifying:

\boxed{a:b=\frac{1}{3}}

3 0
3 years ago
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