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Blababa [14]
3 years ago
15

Solve for w: 7w < -56

Mathematics
2 answers:
crimeas [40]3 years ago
5 0

Lets solve

\\ \sf\longmapsto 7w

  • Take 7 to right side

\\ \sf\longmapsto w

  • Simplify

\\ \sf\longmapsto w

asambeis [7]3 years ago
4 0

Answer:

\boxed {\boxed {\sf w < -8}}

Step-by-step explanation:

We are given an inequality and asked to solve for the variable w.

7w < -56

In order to solve for w, we must isolate the variable. It is being multiplied by 7. The inverse of multiplication is division, so we divide both sides of the inequality by 7.

\frac {7w}{7} < \frac {-56}{7}

w < \frac{-56}{7}

w < -8

w is less than -8 or w < -8.

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Find the width of a rectangle with perimeter 92 and length 19
lora16 [44]

Answer:

Step-by-step explanation:

perimeter = l + b + l + b    or 2(l + b)

92 = 19 + 19 + 2b

92 = 38 + 2b

2b = 92 - 38

2b = 54

b = 54 / 2

b = 27

breadth or width of the triangle =  27

length = 19

3 0
3 years ago
Read 2 more answers
Michael is putting 12 boxes in a storage shed. Each box is in the shape of a rectangular prism with dimensions 1.5 feet by 1.5 f
pishuonlain [190]

Answer:

Volume of room will be left after Michael stores the boxes 426 feet cube

Step-by-step explanation:

It is given that

Michael is putting 12 boxes in a storage shed.

Each box is in the shape of a rectangular prism with dimensions 1.5 feet by 1.5 feet by 2 feet.  

If the storage shed has dimensions 6 feet by 10 feet by 8 feet,

<u>To find the volume of one box </u>

Volume = 1.5 x 1.5 x 2= 4.5 feet cube

Volume of 12 such box = 4.5 x 12 =54 feet cube

<u>To find the volume of shed </u>

Volume of Shed = 6 x 10 x 8 =480

<u> To find remaining portion of shed</u>

Volume of room will be left after Michael stores the boxes      =volume of shed - volume of box

 =480 - 54 = 426 feet cube

7 0
3 years ago
Answer to (4f+1)–(4f+1)
iren2701 [21]

Answer:

0

Step-by-step explanation:

subtracting like terms

5 0
3 years ago
Read 2 more answers
The area of a rectangle is 14 m2 , and the length of the rectangle is 3 m less than double the width. find the dimensions of the
muminat
Width =3.5, length = 4

Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl

Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into
(2w - 7) (w + 2)

Solving for w
2w - 7 = 0
2w = 7
w = 3.5

w+2 = 0
w = -2

So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5

Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14

So the width is 3.5 and the length is 4.

3 0
3 years ago
Question 1 through 6 . <br> THANKS.
Sergio039 [100]
Remember, these are quadrilaterals, so they must add up to 360°. Just add up the angles and then do 360 minus that number to solve for x. Therefore: 1. 118 + 90 + 99 = 307 360 - 307 = 53 2. 110 + 96 + 78 = 284 360 - 284 = 76 3. 48 + 118 + 97 = 263 360 - 263 = 97 4. 105 + 99 + 64 = 268 360 - 268 = 92 5. 103 + 63 + 113 = 279 360 - 279 = 81 6. 95 + 80 + 88 = 263 360 - 263 = 97
4 0
3 years ago
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