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3241004551 [841]
3 years ago
9

If you spin an eight-part spinner numbered from 1 to 8, and flip a coin, what is the probability that you will get a number less

than 3 and tails? (Eather 1/12, 1/8, 1.6, or 1/3.)

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
May 1/8 idk if i'm right good luck

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enrique earned $101.40 in interest over 6 years in a savings account that pays 1.3 % simple interest per year. how much did Enri
victus00 [196]
Simple interest, I = 101.40
Time, t = 6 years
interest, i = 1.3%

Interest, I=Pit, rearrange
Principal, P=I/(it)=101.40/(6*0.013)=1300
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3 years ago
What of these numbers is a prime number 1,11,21,51
Zepler [3.9K]
11. It is not the multiple of any numbers smaller than it
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The circumference of the bike tire above is 83.524 inches. What is the radius of the bike tire? (Use 3.14 for .) A. 262.27 in B.
Shtirlitz [24]

Answer:

Option <u>C. 13.3 in</u>.

Step-by-step explanation:

Here's the required formula to find the radius of the bike tire :

\longrightarrow{\pmb{\sf{C_{(Circle)} = 2\pi r}}}

  • C = circumference
  • π = 3.14
  • r = radius

Substituting all the given values in the formula to find the radius of the bike tire :

\begin{gathered} \qquad{\longrightarrow{\sf{C_{(Circle)} = 2\pi r}}} \\  \\ \qquad{\longrightarrow{\sf{83.524 = 2 \times 3.14 \times  r}}}  \\  \\ \qquad{\longrightarrow{\sf{83.524 = 6.28 \times  r}}} \\  \\ \qquad{\longrightarrow{\sf{83.524 = 6.28r}}} \\  \\  \qquad{\longrightarrow{\sf{r =  \frac{83.524}{6.28}}}} \\  \\ \qquad{\longrightarrow{\sf{r  =  13.3 \: in}}} \\  \\ \qquad  \star{\underline{\boxed{\sf{\red{r  = 13.3 \: in}}}}}\end{gathered}

Hence, the radius of bike tire is 13.3 inches.

\rule{300}{2.5}

6 0
2 years ago
Read 2 more answers
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
2 years ago
How do you solve the system of equations for y=2x-4 y=4x-10?
SVEN [57.7K]
Set the equal to each other

2x-4=4x-10
6=2x
x=3
y=2(3)-4
  =6-4
y =2
8 0
3 years ago
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