Area of ∆=1/2bh
80yd^2=1/2(b)(10yd)
80yd^2=5yd(b)
80yd^2÷5yd=b
16yd=b
Answer:
130
Step-by-step explanation:
10 x 13 = 130
13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 = 130
Answer:
thx i see there everywhere
Step-by-step explanation:
Answer:
The 95% confidence interval for the mean is between 0.985g/cm² and 1.047 g/cm².
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.95}{2} = 0.025](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.95%7D%7B2%7D%20%3D%200.025)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 1.96](https://tex.z-dn.net/?f=z%20%3D%201.96)
Now, find M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 1.96*\frac{0.155}{\sqrt{94}} = 0.0310](https://tex.z-dn.net/?f=M%20%3D%201.96%2A%5Cfrac%7B0.155%7D%7B%5Csqrt%7B94%7D%7D%20%3D%200.0310)
The lower end of the interval is the mean subtracted by M. So it is 1.016 - 0.0310 = 0.985 g/cm²
The upper end of the interval is the mean added to M. So it is 1.016 + 0.0310 = 1.047 g/cm²
The 95% confidence interval for the mean is between 0.985g/cm² and 1.047 g/cm².