Answer:
quadrant 1 that the graph is mainly in
68= 4x-2+30 (notice they are vertical angles)
68= 4x+28
40=4x
10=x
68+y= 180 (forms a straight angle)
y=112
Final answer: x=10, y=112
Answer:
1. .31
2. .68
3. .08
4. true???
5. 2.83
6. .75
7. true again??
8. .09
9. 4.55
10 .10
11. 9.33
12. .92
13. 14.16
Step-by-step explanation:
i didnt really understand 4 and 7 sooo true?
Answer:
3x - 24
Step-by-step explanation:
this is probably wrong
The maximum height of the rocket is 43.89 feet
<h3>How to write the function</h3>
The general function is given as:
h(t) = -16t^2 + vt + h
The initial velocity is
v = 53
So, we have:
h(t) = -16t^2 + 53t + h
The initial height is
h = 0
So, we have:
h(t) = -16t^2 + 53t
Hence, the function of the height is h(t) = -16t^2 + 53t
<h3>The maximum height of the rocket</h3>
In (a), we have:
h(t) = -16t^2 + 53t
Differentiate the function
h'(t) = -32t + 53
Set to 0
-32t + 53 = 0
This gives
-32t = -53
Divide by -32
t = 1.65625
Substitute t = 1.65625 in h(t) = -16t^2 + 53t
h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625
Evaluate
h(1.65625) = 43.890625
Approximate
h(1.65625) = 43.89
Hence, the maximum height of the rocket is 43.89 feet
<h3>Time to hit the ground</h3>
In (a), we have
h(t) = -16t^2 + 53t
Set to 0
-16t^2 + 53t = 0
Divide through by -t
16t - 53 = 0
Add 53 to both sides
16t = 53
Divide by 16
t = 3.3125
Hence, the time to hit the ground is 3.3125 seconds
<h3>The graph of the function h(t)</h3>
See attachment for the graph of the function h(t)
Read more about height functions at:
brainly.com/question/12446886
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