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SSSSS [86.1K]
3 years ago
10

Given the line y = − 2 5 x + 3, determine if the given line is parallel, perpendicular, or neither. Select the correct answer fo

r each lettered part. A. y = 2 5 x + 7 A Parallel B Perpendicular C Neither B. 5y + 2x = −10 A Parallel B Perpendicular C Neither C. −5x + 2y = 4 A Parallel B Perpendicular C Neither
Mathematics
1 answer:
stiks02 [169]3 years ago
6 0

Answer:

(a) Neither

(a) Perpemdicular

Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

y = -\frac{2}{5}x + 3

and

y = \frac{2}{5}x + 7

An equation written in form: y=mx + b has the slope:

m \to slope

So, in both equations:

m_1 = -\frac{2}{5}

m_2 = \frac{2}{5}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{2}{5}

For both lines to be perpendicular

m_1 * m_2 = -1

This is false in this case, because:

-\frac{2}{5} * \frac{2}{5} \ne -1

(b)

5y + 2x = -10

and

-5x + 2y = 4

Write equations in form: y=mx + b

5y + 2x = -10

5y = -2x +10

Divide by 5

y = -\frac{2}{5}x +2

-5x + 2y = 4

2y = 5x + 4

Divide by 2

y = \frac{5}{2}x + 2

In both equations:

m_1 = -\frac{2}{5}

m_2 = \frac{5}{2}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{5}{2}

For both lines to be perpendicular

m_1 * m_2 = -1

This is true in this case, because:

-\frac{2}{5} * \frac{5}{2} = -1

Cancel out 2 and 5

-1 = -1

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According to Thomson Financial, last year the majority of companies reporting profits had beaten estimates. A sample of 162 comp
vova2212 [387]

Answer:

0.1790

0.0738 , 0.5800, 0.7040

354

Step-by-step explanation:

a. Given:  

n = 162

x = 29

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:  

p =  x/n

  = 29/162

  = 0.1790

b. Given:  

n=162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:  

p =  x/n

  =110/162

  =0.6790

For confidence level 1 –\alpha = 0.95, determine z_\alpha/2 = z_0.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):  

z_\alpha/2 = 1.96  

The margin of error is then:

E =  z_\alpha/2*√p(1-p)/n =1.96* √0.6790(1-0.6790)/162 =0.0738

The boundaries of the confidence interval are then:  

p-z_\alpha/2*√p(1-p)/n = 0.6790-1.645√ 0.6790(1- 0.6790)/162 = 0.5800

p+z_\alpha/2*√p(1-p)/n = 0.6790+1.645√ 0.6790(1- 0.6790)/162 = 0.7040

c. Given:  

n = 162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:  

p =x/n

  =0.6790

Formula sample size:

p known: n = [z_\alpha/2 ]^2*pq/E^2

                   = [z_\alpha/2 ]^2*p(1-p)/E^2

                n = [z_\alpha/2 ]^2*0.25/E^2

For confidence level 1 –\alpha= 0.95, determine z_\alpha/2 = z_o.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):  

z_\alpha/2  = 1.96

p is known, then the sample size is (round up!):

n =[z_\alpha/2 ]^2*p(1-p)/E^2

  = 354

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