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Arte-miy333 [17]
3 years ago
15

Hey you ‼️ yeah I unfortunately need your help again these are hard:(

Mathematics
2 answers:
Helga [31]3 years ago
8 0

Answer:

Step-by-step explanation:

The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines

Slope of line 1:

(Yb -Ya)/(Xb - Xa) =

(-10 - (-14))/(-1 - (-3)) =

4/2 =

2

Use that slope to find the Y-intercept of line 1

y = 2x + b

-14 = 2(-3) +b

-14 = -6 + b

-8 = b

Therefore Line 1 is:

y = 2x - 8

Slope of line 2

(11 - 13)/(-1 - (-3)) =

-2/2 =

-1

Y-intercept of line 2

y = -x + b

13 = -(-3) +b

13 = 3 + b

10 = b

Therefore line 2 is

y = -x + 10

Now we have 2 equations to solve for the coordinates x and y

y = 2x - 8

y = -x + 10

Substitute y out in one of the equations

2x - 8 = -x + 10

3x = 18

x = 6

Plug x into one of the equations

y = 2(6) - 8

y = 12 - 8

y = 4

Therefore the solution is:

x=6, y=4

77julia77 [94]3 years ago
3 0
The first one is 2 I’m pretty sure I would help with more but my phone is dying soon lol
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Answer:

3³

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

Given

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3 0
4 years ago
Full working out please ^^ for the first question , ty
sp2606 [1]

Answer:

E

Step-by-step explanation:

Given

y = 2x² - kx + 3

with a = 2, b = - k and c = 3

Since the curve touches the x- axis at one place then the roots are real and equal and the discriminant for this condition is

b² - 4ac = 0, that is

(- k)² - (4 × 2 × 3) = 0

k² - 24 = 0 ( add 24 to both sides )

k² = 24 ( take the square root of both sides )

k = ± \sqrt{24} = ± 2\sqrt{6}

k = 2\sqrt{6} or k = - 2\sqrt{6} → E

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Norma-Jean [14]
4*9/12 is ,I'm pretty sure,the answer
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4 years ago
I WILL ONLY GIVE BRAINLIEST IF YOU SHOW YOUR WORK
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Answer:

Books due to this week=1260

Step-by-step explanation:

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What are the x-intercept and vertex of this quadratic function? Write each feature as an ordered pair: (a,b). The x-intercept of
Allisa [31]

The x-intercept of the function g(x) = -5(x - 3)^2 is (3, 0) and the vertex of the function g(x) = -5(x - 3)^2 is (3, 0)

<h3>How to determine the x-intercept?</h3>

The function is given as:

g(x) = -5(x - 3)^2

Set g(x) to 0, to determine the x-intercept.

-5(x - 3)^2 = 0

Divide through by -5

(x - 3)^2 = 0

Take the square root of both sides

x - 3 = 0

Add 3 to both sides

x = 3

Hence, the x-intercept of the function g(x) = -5(x - 3)^2 is (3, 0)

<h3>How to determine the vertex?</h3>

The function is given as:

g(x) = -5(x - 3)^2

A quadratic function is represented as:

g(x) = a(x - h)^2 + k

Where, the vertex is

Vertex = (h, k)

By comparing g(x) = a(x - h)^2 + k and g(x) = -5(x - 3)^2, we have

(h, k) = (3, 0)

Hence, the vertex of the function g(x) = -5(x - 3)^2 is (3, 0)

Read more about x-intercept and vertex at

brainly.com/question/1305604

#SPJ1

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