Question

If y varies inversely as x2 and y=6 when x=30, what is y when x=6

Answer 1

Answer:

     y= 150

Step-by-step explanation:

$y\ \alpha \ \frac{1}{x^2}\\\\y = k \times \frac{1}{x^2}$

Given y = 6, and x = 30. Find k.

$6 = k \times \frac{1}{30^2}\\\\6 \times 900 = k\\\\5400 = k$

Given  x = 6 and k = 180. Find y

$y = 5400\times \frac{1}{6^2}$

 $=5400 \times \frac{1}{36}\\\\=150$

Answer 2

Answer:

y = 150

Step-by-step explanation:

y varies inversely as x²

yx² = k

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y = 6 when x = 30

6(30²) = k

6(900) = 5400

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what is y when x = 6

y(6²) = 5400

y(36) = 5400

y = 5400/36

y = 150