Answer: 103
Step-by-step explanation:
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
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Answer:
The simplified form would ve -19 - 4x
Step-by-step explanation:
Before we combine anything, we first must expand the expression by distributing the -3 to the terms in the parenthesis.
-7 - 3(4 - 2x) - 10x
-7 - 12 + 6x - 10x
Now we can combine the terms with and without variables.
-19 - 4x
