Answer:
7.62
Step-by-step explanation:
use the Pythagorean theorem
3^2+7^2=58
the square root of 58 is about 7.62
F(-1)= -3 is (-1,-3) and f(2) = 6 is (2,6) where f(x) = y
y=mx + b is the slope-intercept form whereas m equals the slope (rate of change) and b equals the y-intercept (initial amount/what y is when x is 0.)
First, we need to find the slope between the two points (-1,-3) and (2,6). To find the slope we could use one of it's formulas

.
1. (-1,-3)
2. (2,6)

→

→

The slope is 3 (

). Thusly, y = 3x + b
To find out the y-intercept, we can reverse the slope. [Note: This

is in

where rise is 'y' and run is 'x'. Reversed would be

]. Take the second ordered pair and use our reversed slope on it until we get 0 for x.
(2, 6) ⇒ (2 - 1, 6 -3) ⇒ (1, 3) ⇒ (0,0)
Y-intercept is 0. Therefore,
y= 3x + 0 [NOTE: y = f(x), so if you want it in function notation form it's just f(x) = 3x + 0.]
Hello :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a <span>≠ 0) is :
</span><span>Δ = b² -4ac
1 ) </span>Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ <span>< 0 : no reals solutions</span>
Answer:

Step-by-step explanation:

This is a homogeneous linear equation. So, assume a solution will be proportional to:

Now, substitute
into the differential equation:

Using the characteristic equation:

Factor out 

Where:

Therefore the zeros must come from the polynomial:

Solving for
:

These roots give the next solutions:

Where
and
are arbitrary constants. Now, the general solution is the sum of the previous solutions:

Using Euler's identity:


Redefine:

Since these are arbitrary constants

Now, let's find its derivative in order to find
and 

Evaluating
:

Evaluating
:

Finally, the solution is given by:

Answer:

Step-by-step explanation:
<em>Hey there!</em>
Well if the length is 18 and 3 inches we need to find the sum of both lengths,
18ft 3in + 18ft 3in = 36ft 6in
Width- 10ft 8in + 10ft 8in = 20ft 16 in -> 21ft 4in
l + w = 57ft 10in
<em>Hope this helps :)</em>