<span>The resent value, also called "discounted value," is the current worth of the camera. So, we know that the discounted value is $105.00.
The first price of the camera was $120.00.
This means that the price is decreased. In order to calculate the discount rate we should find out how many percent the camera was discounted. 105 from 120 is: 105/120*100=87.5
So, the discount is 100-87.5=12.5 %.
</span>
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X

<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Answer: answer C is correct
Step-by-step explanation:
Where is the figure pls attach it by using the paper clip icon
F(0)= -4(0)+9
F(0)= 0+9
F(0)=9