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3 years ago

Can someone salve this pleaseeeeeeeee

Mathematics

2 answers:

stepladder [879]3 years ago

8 0

Answer:

x=3/2

Step-by-step explanation:

2(1/49)^x-2=14

The answer is 3/2

Mila [183]3 years ago

3 0

Answer:

x=3/2

Step-by-step explanation:

You might be interested in

Ma=np,for a is what

Julli [10]

Answer:

$\displaystyle \frac{np}{m} = a$

Step-by-step explanation:

You divide both sides by m to get the above answer:

$\displaystyle \frac{ma}{m} = \frac{np}{m} \\ \\ a = \frac{np}{m}$

I am joyous to assist you anytime.

8 0

3 years ago

HELPP! BRAINLIEST AND 10 POINTS !!

Scrat [10]

Answer:

I think it's 3 units so you got that right

4 0

3 years ago

Read 2 more answers

Need help on this question

sergey [27]

Total Area: T.A.=2*Ab+Al

Area of the base: Ab=p*K

Semi-perimeter of the base: p
p=P/2
Perimeter of the base: P=20
p=P/2=20/2→p=10
Ab=p*k=10*K→Ab=10K

Lateral Area of the prism: Al
Al=P*h
Height of the prism: h=6
Al=P*h=20*6→
Al=120

T.A.=2*Ab+Al
T.A.=2*(10K)+120
T.A.=20K+120
T.A.=120+20K

Answer: (120+20K)

7 0

3 years ago

A convex hexagon has exterior angles of 39°, 47°, 42°, 59°, and 64°. What is the measure of an exterior angle at the

meriva

Answer: $109^{\circ}$

Step-by-step explanation:

The exterior angles of a polygon add to 360 degrees, so the sixth angle measures $360-39-47-42-59-64=\boxed{109^{\circ}}$

7 0

2 years ago

❊ Simplify :

DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

$\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}$

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

$\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}$

Now, create a common denominator. To do this, we can multiply the first term by (a + 1) and the second term by (a + 2). Hence:

$\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}$

Add the fractions:

$\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}$

Factor:

$\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}$

Simplify:

$\displaystyle =\frac{a+4}{(a-1)(a+1)}$

We can expand. Therefore:

$\displaystyle =\frac{a+4}{a^2-1}$

Problem 2)

We want to simplify:

$\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}$

Again, let's create a common denominator. First, let's factor out a negative from the second term:

$\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}$