Answer:
402.07
Step-by-step explanation:
Answer:
The probability that she wins exactly once before she loses her initial capital is 0.243.
Step-by-step explanation:
The gambler commences with $30, i.e. she played 3 games.
Let <em>X</em> = number of games won by the gambler.
The probability of winning a game is, <em>p</em> = 0.10.
The random variable <em>X</em> follows a Binomial distribution, with probability mass function:

Compute the probability of exactly one winning as follows:

Thus, the probability that she wins exactly once before she loses her initial capital is 0.243.
So in order to get this answer you must develop what is so called the breathing style
9y + x2y- xy2 because x2y and xy2 arent the same numbers even though they are the same numbers but the letters are in different orders
Answer:

Step-by-step explanation:
first, convert 37.10 into a fraction. it will be
. next, divide the two fractions using keep, change, flip. (keep the first fraction, change the sign into the multiplication sign, and flip the second fraction) you will get
×
=
. you need the multiply the numerator by the numerator and the denominator by the denominator. next, to simplify, divide both the numerator and denominator by 2 and you will get
:)