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ValentinkaMS [17]
3 years ago
10

Which problems can be solved by performing this multiplication?

Mathematics
2 answers:
zvonat [6]3 years ago
7 0
Second and third are correct
1) 3/4 + 24
2) 3/4 * 24
3) 3/4 * 24
4) 1/4*24
nika2105 [10]3 years ago
6 0

Answer: the fourth one

Step-by-step explanation:

You might be interested in
{3x=7y=5<br> {5x-2y=-19
Anton [14]

Answer:

(-3, 2)

Step-by-step explanation:

{3x=7y=5

{5x-2y=-19

solve....

maybe it was  3x + 7y = 5

and  5x - 2y = -19

2*(3x + 7y = 5)

7*(5x - 2y = -19)

-------------

6x + 14y = 10

35x -14y = -133

41x = -123

x = -3

y = ...

5*(-3) - 2y = -19

-15 - 2y = -19

2y = 4

y = 2

(-3, 2)

7 0
3 years ago
a store received 500 containers of milk to be sold by Febuary 1. Each container the store sold $0.83 and sold for $1.67. The sto
FrozenT [24]
$409.80.

The amount of net profit the store makes on each container is given by 1.67-0.83 (the amount it is sold for subtracted by the amount it costs the store), which is $0.84 per container.  They sell 470 containers, so the net profit at this point is 470(0.84) = $394.80.

However, since the distributor is giving the store a $0.50 refund on all every container under 500 that the store sells, the store gets additional money back:

500-470 = 30 containers not sold
30(0.50) = 15

So the total profit is $394.80 + 15 = $409.80.
6 0
3 years ago
How do I solve -4 times the square root of 1/10
schepotkina [342]

Answer: I think it is -0.4

Step-by-step explanation:

7 0
3 years ago
Evaluate 3 – 5 · 2 + 8 ÷ 4 – 2 using the correct order of operations.
soldi70 [24.7K]
The answer is
C) -7

Multiply -5 by 2
Divide 8 by 4 :
3-10+2-2
Subtract 10 from 3 :
-7+2-2
Add -7 and 2 :
-5 - 2
Subtract 2 from -5:
-7

3 0
3 years ago
A circle is centered at N(-6, -2). The point E(-1,1) is on the circle.
galina1969 [7]

Answer:

Outside the circle

Step-by-step explanation:

Let's first write the equation of this circle: (x-h)^2+(y-k)^2=r^2, where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:

NE = \sqrt{(-6-(-1))^2+(-2-1)^2} =\sqrt{25+9} =\sqrt{34}

The radius is √34, which means that r² = 34. So, our equation is:

(x + 6)² + (y + 2)² = 34

Plug in -10 for x and -7 for y:

(x + 6)² + (y + 2)² = 34

x² + 12x + 36 + y² + 4y + 4 = 34

x² + 12x + y² + 4y + 40 = 34

x² + 12x + y² + 4y + 6 = 0

(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7

Since 7 > 0, we know that H lies outside the circle.

6 0
3 years ago
Read 2 more answers
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