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ValentinkaMS [17]
3 years ago
10

Which problems can be solved by performing this multiplication?

Mathematics
2 answers:
zvonat [6]3 years ago
7 0
Second and third are correct
1) 3/4 + 24
2) 3/4 * 24
3) 3/4 * 24
4) 1/4*24
nika2105 [10]3 years ago
6 0

Answer: the fourth one

Step-by-step explanation:

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Given that line CD is a perpendicular bisector of triangle ABC, if side AB has a length of 11 and side AC has a length of 14 wha
nalin [4]

Answer:

12.87

Step-by-step explanation:

Since we know that line CD is a perpendicular bisector, triangle ACD is a right triangle, and thus we can apply the Pythagorean theorem to determine the length of side CD. Since the Pythagorean theorem states that a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the adjacent sides, we can plug in the values of side AD and AC.

As side CD is the bisector of side AB, sides AD and DB are both half the length of side AB, so:
AD = 11/2
AD = 5.5

We now know two values of our equation, and thus we can solve for the missing third value.

5.5^2 + b^2 = 14^2
14^2 - 5.5^2 = b^2
196 - 30.25 = b^2
165.75 = b^2
\sqrt{165.75} = b
b = 12.87

4 0
2 years ago
Please help fast, thank you! I only have 20 minutes! I always appreciate your help!
shusha [124]

Answer:

ur missing the question

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Which of the following algebraic expressions can be used to express the statement "five less than y squared?" 5 − 2y 2y − 5 y2 −
beks73 [17]
Y2- 5. The answer is this
5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST. IM AN EXPERT AND THSI IS STILL HARD. 18+20.
fenix001 [56]

Answer:

38

Step-by-step explanation:

5 0
3 years ago
Please help me....I really need help!!
scoundrel [369]

\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}

6 0
3 years ago
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