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3 years ago

10

The ratio of men to women working for a company is 2 to 3 . If there are 120 employees total, how many women work for the compan

y?

1 answer:

gtnhenbr [62]3 years ago

3 0

I think the answer is 20

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Mias mom paid 22.50 for 5 pizzas for a family

agasfer [191]

$4.5 per pizza. I did 22.50/5

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3 years ago

Cory is a bird-watcher. He estimates that 30% of the birds he sees are American robins, 20% are dark-eyed juncos, and 20% are so

Free_Kalibri [48]

Answer: 0.65

Step-by-step explanation:

the probability is high

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2 years ago

Help me please this is due tommorow morning

nataly862011 [7]

Answer:

E: (2, -1)

F: (3, -1)

G: (3, -2)

H: (2, -2)

Step-by-step explanation:

Reflect all coordinates over an x-axis

Because you are reflection 180 degrees over the x axis, the y-axis is going to stay the same (because you are not moving the square left or right. When reflecting over axis always add the same amount you took away from the other side, if that makes any sense.

7 0

3 years ago

If a trapezoid with 9.00-cm and 12.00-cm bases has an area of 68.25 cm2, what is its height to the nearest hundredth?

Lapatulllka [165]

I hope this helps you

68,25=(9+12).h/2

2.68,25=21.h

136,5/21=h

h=6,5

4 0

3 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago