Select all the sets of numbers that are possible values for x in the inequality, x>- 2.

Lin notices that the number of cups of red paint is always 15 of the total number of cups (0.2 of the total number of cups). She

ivann1987 [24]

Step-by-step explanation:

The number of cups of red paint is always 15 of the total number of cups. 0.2 of the total number of cups.

She writes the equation r = 15t (r = 0.2t) to describe the relationship.

In this case, the total no. of cups is an independent variable. No. of cups do not depend on any term.

The number of cups of red paint is a dependent variable as it depends on the number of cups.

7 0

2 years ago

What is the radical expression

Margaret [11]

$5x^{\frac{1}{4} }=5\cdot x^{\frac{1}{4}}= 5\sqrt[4]{x} \\\\because\\\\a^{\frac{1}{n} }=\sqrt[n]{a}$

6 0

3 years ago

What Is the least common multiple of two numbers when one number is a multiple of the other give an example

Tems11 [23]

Like 9 and 9? 9 is a multiple of 3 and 9 time 9 is 81

6 0

3 years ago

Read 2 more answers

Factor by GCF<br> 2n2-8n3

ehidna [41]

-2n2 • (4n - 1). Hope this helped

3 0

3 years ago

Granola Crunch cereal is packaged in 1 pound boxes. Susan Torres, a quality control analyst who works for the manufacturer of th

sineoko [7]

Answer:

$z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162$

$p_v =2*P(z>3.162)=0.0016$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=1.02$ represent the sample mean

$\sigma=0.04$ represent the population standard deviation

$n=40$ sample size

$\mu_o =1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is equal to 1 pound or no :

Null hypothesis: $\mu =1$

Alternative hypothesis: $\mu \neq 1$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162$

P-value

Since is a two-sided test the p value would be:

$p_v =2*P(z>3.162)=0.0016$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.

5 0

3 years ago