Answer:
shouls be C if im correct
Answer: 0.065
Step-by-step explanation:
Given : Sample size : n= 320
The sample proportion of people who rent their home : 
Significance level : 
Then , Critical value : 
The formula to find the margin of error : -
Hence, the margin of error for the confidence interval for the population proportion with a 98% confidence level =0.065
we are given
we can also write as
now, we can use synthetic division method
so, we get
..................Answer
3. well you know to get the perimeter of a rectangle, you add together 2L and 2W. A way you could write this is-- 2x + 2(x+5). You would just need to simplify it--2x + 2x+10 --4x+10.
4. To find out how much they have in all, you just need to add them together--x+24.50 + 7x-52.34. Now you need to simplify the problem by putting the values together. x+7x + 24.50-52.34-- you can do that.
5. To do this one, look back at 3. and just change the numbers. Drawing a picture may help. The sides are x+y and the top and bottom are 5y+12.
6. same as 5.
7. I think this one is just solving for x first. make Tom and his brother's equations equal to zero and get x by itself. Tom's equation would be 8x-30=0 ----His brother's would be 5x+10. You need to find out what x equals then plug it back into the equations. To plug it in, have x's value take x's place then find the number of candies they have.
8. The easiest way to start is by writing the same values together. 4x+3x-5x-5-7+2---then just add the x's together and add the numbers together.
9. Multiply the outer numbers to both of the values in the parentheses. 2(x-4) would turn out to 2x-8. then do the same as 8. and put the same values together to simplify.
10. get x by itself. Start by multiplying 3 by x and 4 in the parentheses. simplify the numbers then subtract it from both sides to get x alone.
Answer:
Probability that a randomly selected broiler weighs more than 1454 g is 0.3372 or 34% (approx.)
Step-by-step explanation:
Given:
Weights of Broilers are normally distributed.
Mean = 1387 g
Standard Deviation = 161 g
To find: Probability that a randomly selected broiler weighs more than 1454 g.
we have ,
X = 1454
We use z-score to find this probability.
we know that
P( z = 0.42 ) = 0.6628 (from z-score table)
Thus, P( X ≥ 1454 ) = P( z ≥ 0.42 ) = 1 - 0.6628 = 0.3372
Therefore, Probability that a randomly selected broiler weighs more than 1454 g is 0.3372 or 34% (approx.)
