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3 years ago

5

What practical effect does Discovery impose on the Right of Occupancy?

1 answer:

shutvik [7]3 years ago

4 0

Answer:

discovery impose on the right of the number line

Step-by-step explanation:

You might be interested in

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

Graph each absolute value function. State the domain, range, and y-intercept.

grandymaker [24]

Answer:

i) D: All real numbers

ii) R: $y\le5$

iii) Y-int: b=2

Step-by-step explanation:

i) The given absolute value function is

$y=-|x+3|+5$

The domain is all values of x that makes the function defined.

The absolute value function is defined for all values of x.

The domain is all real numbers.

ii) The given function is $y=-|x+3|+5$

The function has vertex $(-3,5)$ .

The function is reflected in the x-axis.

This means the vertex is the maximum point on the graph of the function.

The maximum y-value is 5.

The range is therefore $y\le 5$ or $(-\infty,5]$

iii) To find the y-intercept, put $x=0$ into the function.

$y=-|0+3|+5$

$y=-|3|+5$

$y=-3+5$

$y=2$

The y-intercept is (0,2) or $b=2$

See attachment for graph.

6 0

3 years ago

Pleaseeee help please

kumpel [21]

Answer: It will be 60m^2

5 0

3 years ago

Which inequalities are true plz help!!!

alex41 [277]

Answer:2,3, and 5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

On a trip to the dump Ralph took 56 pounds of garbage. His partner, Kyle, has 64 pounds. How many pounds of garbage did they get

katen-ka-za [31]

Answer:

120 pounds

Step-by-step explanation:

56 + 64 = 120 pounds

5 0

3 years ago

Read 2 more answers