A square pyramid with a side length of 6 inches has volume of 102 cubic inches. Find the height of the square pyramid.

Suppose the Willard gold nugget was turned into 4 equal sized gold bricks. If one of the bricks was sold how many ounces of the

Zielflug [23.3K]

788/4 = 197

788 - 197 = 591

8 0

2 years ago

Read 2 more answers

An exterior angle of an isosceles triangle has measure 130°. Find two possible sets of measures for the angles of the triangle.

frozen [14]

(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°: base=(180-50)/2=65°
base is 50°: vertex= 180-2*50=80°

vertex 50 base 65; vertex 80, base 50

(2)base=180-130=50°
vertex=180-2*50=80°

base 50 vertex 80

5 0

2 years ago

uppose a large telephone manufacturer has a problem with excessive customer complaints and consequent returns of the phones for

vodka [1.7K]

Answer:

The answer is "294.2075".

Step-by-step explanation:

Given:

$\hat{p} = 0.5 \\\\1 - \hat{p} = 1 - 0.5 = 0.5\\\\E = 4\% = 0.04\\\\$

At $83\%$ confidence level the z is ,

$\alpha = 1 - 83\% = 1 - 0.83 = 0.17\\\\\frac{\alpha}{2} = \frac{0.17}{2} = 0.085\\\\Z_{\frac{\alpha}{2}} = Z_{0.085} = 1.3722\\\\n = (\frac{Z_{\frac{\alpha}{2}}}{E})^2 \times \hat{p} \times (1 - \hat{p})\\\\$

$= (\frac{1.3722}{0.04})^2 \times 0.5 \times 0.5\\\\= (34.305)^2 \times 0.5 \times 0.5\\\\= 1,176.83 \times 0.5 \times 0.5\\\\= 1,176.83 \times 0.25\\\\=294.2075$

5 0

3 years ago

Which is the diameter of a rectangle whose circumference is 13653 cm and one side is 5431 cm

leonid [27]

Answer:

See below

Step-by-step explanation:

If by circumference you meant perimeter and diameter you mean length, then here is my answer.

Perimeter = 2L+ 2W

13653= 2*L + 2*5431

13653= 2L + 10862 Subtract 10862 from both sides

2791= 2L Divide by 2

L= 1395.5

The diameter is 1395.5

6 0

3 years ago

Write the slope-intercept form of the equation of the line described.

Ad libitum [116K]

7)

Given the line

$y=-x+2$

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = -1

We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -1 and the point (4, 0)

$y-0 = -1 (x-4)$

Writing in the slope-intercept form

$y = -x+4$

Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:

$y = -x+4$

8)

Note: Your line is a little bit unclear. But, I am assuming the

ine is: y = -x-1

Given the assumed line

y = -x-1

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = m = -1

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -1

perpendicular slope = – 1/m = -1/-1 = 1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1 and the point (4, 3)

$y - 3 = 1 (x-4)$

Writing in the slope-intercept form

y-3 = x-4

y = x-4+3

y = x - 1

Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:

y = x - 1

5 0

2 years ago