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3 years ago

(Ignore the C that was answered I don’t think it’s correct)

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

7 0

Answer:

c is actually correct lol

Step-by-step explanation:

g(x) = (x-4)(x+2)

set both (x-4) and (x+2) equal to zero

x-4=0

x=4

& bx+2=0

x=-2

c has 4 and -2 as x values

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Wich is equivalent to 12(3 2/3)!?

Lemur [1.5K]

Answer:

1/5 = 2/10 = 3/15 = 4/20

= 5/25 = 6/30 = 7/35 = 8/40

= 9/45 = 10/50 = 11/55 = 12/60

= 13/65 = 14/70 = 15/75 = 16/80

= 17/85 = 18/90 = 19/95 = 20/100

= 21/105 = 22/110 = 23/115 = 24/120

= 25/125 = 26/130 = 27/135 = 28/140

= 29/145 = 30/150 = 31/155 = 32/160

= 33/165 = 34/170 = 35/175 = 36/180

= 37/185 = 38/190 = 39/195 = 40/200

= 41/205 = 42/210 = 43/215 = 44/220

= 45/225 = 46/230 = 47/235 = 48/240

= 49/245 = 50/250 = 51/255 = 52/260

= 53/265 = 54/270 = 55/275 = 56/280

= 57/285 = 58/290 = 59/295 = 60/300

= 61/305 = 62/310 = 63/315 = 64/320

= 65/325 = 66/330 = 67/335 = 68/340

= 69/345 = 70/350 = 71/355 = 72/360

= 73/365 = 74/370 = 75/375 = 76/380

= 77/385 = 78/390 = 79/395 = 80/400

= 81/405 = 82/410 = 83/415 = 84/420

= 85/425 = 86/430 = 87/435 = 88/440

= 89/445 = 90/450 = 91/455 = 92/460

= 93/465 = 94/470 = 95/475 = 96/480

= 97/485 = 98/490 = 99/495 = 100/500

Step-by-step explanation:

all of these are equivalent

3 0

3 years ago

Read 2 more answers

Hector gave of his money and an additional $1 to Calista. He

trapecia [35]

I think it’s $34 but i’m not sure

6 0

3 years ago

Read 2 more answers

List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers,

Anarel [89]

Answer: YES

Step-by-step explanation:

We need to write out the expressions

P= {m}

Q= {n}

R= {m+n}

If 2m=n then we can say;

P= {½n} Q= {n} & R= {³/²n}

It is obvious that the smaller number in Q is greater than the largest number in P

We can make some assumptions.

Let n= (x,y,z)

Consequently,

P={½x,½y,½z} Q={x,y,z} and R= {1.5x,1.5y,1.5z}

Therefore the median will be the middle element,

Median of P= ½y

Median of Q = y

Median of R = 1.5y

And 1.5y>1.5y

Then we can agree that the median of R is greater than the median of both P and Q

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3 years ago

What is (57/tan30°)m^2

iVinArrow [24]

57\sqrt{3}m^2. Enjoy!

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3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago