josiah is taking his friends to the movies each ticket cost $10, and popcorn is $5 a bag. there is a 3$ service fee for the enti
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Answer:
The length of BC is needed because it is the side opposite ∠A.
Step-by-step explanation:
Given the right angles triangle as shown in the attachment, we can get sin(A) without using Pythagoras theorem. Instead we will use SOH CAH TOA trigonometry identity.
According to SOH:
Sin(A) = Opposite/Hypotenuse
Sin(A) = |BC|/|AB|
Opposite side of the triangle is the side facing ∠A.
Based on the formula, we will need to get the opposite side of the triangle which is length BC for us to be able to determine sinA since the hypotenuse is given.
Check the picture below.
let's recall that once we move an angle in the opposite direction of the 0-line or x-axis, we end up with a negative counterpart angle.
since we know that θ is on the IV Quadrant, then its negative counterpart must be across the line, and tangent is negative on the IV Quadrant, and positive on the I Quadrant.
Answer:
Small Scale replica of John Hancock tower is approximately 2.33 m.
Step-by-step explanation:
Given:
Height of Willis tower = 1450 ft
Height of John Hancock Center = 1127 ft
Small Scale replica of Willis tower = 3 m
We need to find Small Scale replica of John Hancock tower.
First we will find the per meter scale of Willis tower and then using the same we will use to find the Small Scale replica height of John Hancock tower.
For 3 meter scaling = 1450 ft
So for 1 meter scaling = Number of foots in 1 meter Scaling
By Using Unitary method we get;
Number of foots in 1 meter Scaling =
Now we had 1 meter scaling as 483.333 ft and we need to find meter scaling for 1127.
So again Using Unitary method we get;
Small Scale replica of John Hancock =
Rounding to nearest hundred we get;
Small Scale replica of John Hancock tower is approximately 2.33 m.