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Anna35 [415]
3 years ago
9

X - 4y + z = 5 4x + 2y + z = 2 - 4x + y - 3z = -8

Mathematics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

Input complete question please.

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Is the binomial a factor of the polynomial function?
olchik [2.2K]

Answer:

YES

NO

NO

Step-by-step explanation:

The given polynomial is: $ f(x) =  x^3 + 4x^2 - 25x - 100 $

(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.

To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.

∴ f(5) = 5³ + 4(5)² - 25(5) - 100

        = 125 + 100 - 125 - 100

        = 225 - 225

        = 0

We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.

Now, to check (x + 2) is a factor.

i.e., to check x = - 2 satisfies f(x) or not.

f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100

      = -8 + 16 + 50 - 100

     = -108 + 66

     ≠ 0

Therefore, (x  + 2) is not a factor of f(x).

To check (x - 4) is a factor.

∴ f(4) = 4³ + 4(4)² - 25(4) - 100

        = 64 + 64 - 100 - 100

        = 128 - 200

        ≠ 0

Therefore, (x - 4) is not a factor of f(x).

7 0
3 years ago
A stick was broken into two pieces. The length of the first piece is 28 cm more than the second piece. The total length of the t
Reika [66]
84 cm because you HAVE to add them together.
6 0
2 years ago
Which of the following is an example of empirical probability
olasank [31]
Just wondering, Is there options?
3 0
2 years ago
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Which number line shows the solution to the inequality n > 4?
lesya692 [45]

Answer:

It would be A

Step-by-step explanation:

4 0
2 years ago
Find the distance traveled by a particle with position (x, y as t varies in the given time interval. x = 3?sin2 t, y = 3?cos2 t,
ANTONII [103]
Assuming the particle's position is given by

\begin{cases}x(t)=3-\sin2t\\y(t)=3-\cos2t\\0\le t\le4\end{cases}

then the distance traveled over the interval is

\displaystyle\int_{t=0}^{t=4}\sqrt{\left(\dfrac{\mathrm dx(t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy(t)}{\mathrm dt}\right)^2}\,\mathrm dt
=\displaystyle\int_0^4\sqrt{(-2\cos2t)^2+(2\sin2t)^2}\,\mathrm dt
=\displaystyle\int_0^4\sqrt{4\cos^22t+4\sin^22t}\,\mathrm dt
=\displaystyle2\int_0^4\mathrm dt
=2(4-0)=8
5 0
3 years ago
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