Anyone have tikt ok put u r at in co mments or anw ser and i will follo w u

The pair of items that is likely to have the largest positive cross-price elasticity of demand is:

mash [69]

Coffee and tea are predicted to have the highest positive cross-price elasticity of demand among all the products.

If the price of one good rises while the demand for the other good increases, then the cross price elasticity is positive. When using alternative products, this is feasible. The only alternatives are coffee and tea.

Cross-price elasticity quantifies how sensitive a product's demand is to a change in the price of the related product. Many products on the market have relationships with one another. This could imply that a product's price change could have a positive or negative impact on the demand for another product.

When it comes to substitutes, a rise in price of one substitute drives up demand for the alternative product. Because they always want to maximize utility, consumers frequently do this products. The perceived satisfaction increases with decreasing expenditure.

Learn more about cross-price elasticity here

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6 0

1 year ago

Swisher, Incorporated reports the following annual cost data for its single product: Normal production level 30,000 units Direct

wlad13 [49]

Answer:

Profit decreases by $322,600

Explanation:

Normal production level = 30,000 units

Cost of direct material per unit =$6.40 , total cost = $6.40*30,000=$192,000

Cost of direct labor per unit =$3.93 , total cost =$3.93*30,000=$117,900

Variable over head cost per unit=$5.80, total cost =$5.80*30,000=$174000

Fixed overhead total cost = $150,000

Production cost with 30,000 units will be;

$192,000 + $117,900 + $174000 + $150,000 =$633900

Normal selling price of product per unit = $48

Revenue after normal sell of 30,000 units $48 = 30,000*48=$1440000

Profit obtained : $806,100

Increasing the production to 50,000 units you can calculate the projected cost of production

New production level = 50,000 units

Cost of direct material per unit =$6.40 , total cost = $6.40*50,000=$320,000

Cost of direct labor per unit =$3.93 , total cost =$3.93*50,000=$196,500

Variable over head cost per unit=$5.80, total cost =$5.80*50,000=$290,000

Fixed overhead total cost = $150,000

Production cost with 30,000 units will be;

$320,000 + $196,500 + $290,000 + $150,000 =$956,500

Normal selling price of product per unit = $48

Revenue after normal sell of 30,000 units $48 = 30,000*48=$1440000

Profit obtained =$483,500

Decreased in profit = $806100-$483500 =$322,600

4 0

3 years ago

If a project costs $100 comma 000100,000 and is expected to return $27 comma 00027,000 annually, how long does it take to rec

stealth61 [152]

The formula for discounted payback period is DPP = -ln (1 – Id/C) / ln (1+d), wherein I is the initial investment, d is the discount rate, and C is the cash flow. Substituting values, DPP = - ln(1-((0.12)($100)/$27)) / ln(1+0.12). Therefore, DDP is equal to 5.19 years.

5 0

2 years ago

The Smelting Department of Kiner Company has the following production data for November. Production: Beginning work in process 3

Anvisha [2.4K]

Answer:

(A) 18,600 units

(B) 13,821 units

Explanation:

(A) The computation of the equivalent unit for material cost is shown below:

= (Completed and transferred units × completed percentage) + (ending work in progress units × completed percentage)

= (10,500 units × 100%) + (8,100 units × 100%)

= 10,500 units + 8,100 units

= 18,600 units

(B) The computation of the equivalent unit for conversion cost is shown below:

= (Completed and transferred units × completed percentage) + (ending work in progress units × completed percentage)

= (10,500 units × 100%) + (8,100 units × 41%)

= 10,500 units + 3,321 units

= 13,821 units

6 0

2 years ago

Suppose that a company needs new equipment, and that the machinery in question earns the company revenue at a continuous rate of

julia-pushkina [17]

Answer:

a-The present value of revenue in the first year is $61,085.92.

b-The total time it would take to pay for its price is 2.44 years of 29.33 months.

Explanation:

a-

Let the function of the revenue earned is given as

$S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt$

Here

a and b are the limits of integral which are 0 and 1 respectively
r is the rate of interest which is 5% or 0.05

S(t) is the function of value which is $S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225$
So the present value of revenue in the first year is $61,085.92.
b-
The time in which the machine pays for itself is given as
$PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt+\int\limits^t_1 {S(t)e^{-0.05t}} \, dt\\PV=61085.9225+\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt$
The present value is set equal to the value of machine which is given as
$160,000 so the equation becomes:
$PV=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\160000=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt=160000-61085.9225\\\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt=98914.07\\\\t=-\dfrac{\ln \left(0.93034\right)}{0.05}\\t=1.44496$
So the total time it would take to pay for its price is 2.44 years of 29.33 months.

6 0

3 years ago